The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is
seconds
So, the time required for 200 wing beat
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...

So, the time required for one wing beat is 5 milliseconds.
Answer:
32 oz
Step-by-step explanation:
Im assumin you mean how many oz
Since 3x+17=5x-3, x= 10. so angles