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Alex787 [66]
3 years ago
11

. Which of the following is the only triangle whose sides form a right triangle?​

Mathematics
1 answer:
vivado [14]3 years ago
4 0

Answer:

It is either C or D.

Step-by-step explanation:

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Either Table A or Table B shows a proportional relationship.
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Table B of course they follow by the order instead of table A
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5

Step-by-step explanation:

21-6=15/3=5

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22. If 1 m,m/19 - 118°, and m/16 - 48°, calculate m/12.
Ulleksa [173]

Answer: Option 4

Step-by-step explanation:

m\angle 20=62^{\circ} (linear pair)

m\angle 11=70^{\circ} (angle sum in a triangle)

m\angle 12=110^{\circ} (linear pair)

4 0
2 years ago
According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann
mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of consecutive time intervals in which the water supply remains below a critical value <em>y₀</em>.

The random variable <em>Y</em> follows a Geometric distribution with parameter <em>p</em> = 0.409<em>.</em>

The probability mass function of a Geometric distribution is:

P(Y=y)=(1-p)^{y}p;\ y=0,12...

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) =  P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

              =(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable <em>Y</em> as follows:

\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445

Compute the standard deviation of the random variable <em>Y</em> as follows:

\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

                    = P (Y ≥ 3.325)

                    = P (Y ≥ 3)

                    = 1 - P (Y < 3)

                    = 1 - P (X = 0) - P (X = 1) - P (X = 2)

                    =1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0
3 years ago
Find the circumference and the area of a circle with diameter 2 cm.
ivolga24 [154]

Answer:

c = 6.28cm

area \:  = 3.14 {cm}^{2}

Step-by-step explanation:

circumferece \\  = 2\pi \: r \\  = 2 \times 3.14 \times 1 \\  = 6.28cm

area = \pi {r}^{2}  \\  = \pi \times 1 \times 1  \\  = 3.14 {cm}^{2}

3 0
3 years ago
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