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Alex787 [66]
3 years ago
11

. Which of the following is the only triangle whose sides form a right triangle?​

Mathematics
1 answer:
vivado [14]3 years ago
4 0

Answer:

It is either C or D.

Step-by-step explanation:

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Please help, will give BRAINLIST
SIZIF [17.4K]

Answer: The distribution has an outlier

Step-by-step explanation: If you look at the graph you can clearly see it is the only one really off to the side even without doing any math.

8 0
3 years ago
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Debbie finished her algebra test early so she decided to check each of her answers. After checking her answer to question number
leva [86]
I don’t understand this question.. as you don’t provide much detail.
7 0
3 years ago
Choose the statement that does NOT describe similarity.
kirza4 [7]

To answer your question the answer is the third choice.

c. Two polygons are similar when the only difference is size

8 0
3 years ago
The average demand for rental skis on winter Saturdays at a particular area is 150 pairs, which has been quite stable over time.
pentagon [3]

Answer:

a) 15.87% probability that demand will exceed this supply on any winter Saturday

b) The shop needs to have 197 pairs of skis in stock.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 150, \sigma = 20

(a) The rental shop stocks 170 pairs of skis. What is the probability that demand will exceed this supply on any winter Saturday?

This probability is 1 subtracted by the pvalue of Z when X = 150. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{170 - 150}{20}

Z = 1

Z = 1 has a pvalue of 0.8413

1 - 0.8413 = 0.1587

15.87% probability that demand will exceed this supply on any winter Saturday

(b) How many pairs of skis in stock does the shop have to have to make the probability in question (a) less than .01?

This is X when Z has a pvalue of 0.99.

So X when Z = 2.33

Z = \frac{X - \mu}{\sigma}

2.33 = \frac{X - 150}{20}

X - 150 = 2.33*20

X = 196.6

Rounding up, since the number of pairs is a discrete number

The shop needs to have 197 pairs of skis in stock.

6 0
3 years ago
A type of bear can run at a rate of 21 miles per hour. At this rate, how far could it run in 3 hours?​
zavuch27 [327]

Answer:

63 miles

Step-by-step explanation:

We know that the bear can run at 21 mi/hr. So, multiply 21*3 to get how many miles the bear could run in 3 hrs.

Hope it helped.

6 0
3 years ago
Read 2 more answers
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