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12345 [234]
3 years ago
7

Wilmer already has 214 cards. he needs to collect 334 cards. he plans to collect 8 cards each day. find the minimum number of da

ys wilmer will take to reach his goal.​
Mathematics
1 answer:
Wittaler [7]3 years ago
3 0
The answer is 15 days.

The first step you need to take is to subtract the amount of cards he has from the amount of cards he needs. So 334 (needs) - 214(has) = 120 cards he still needs. So he is collecting 8 cards a day. In order to find out how many days it will take to collect the 120 cards, we need to divide 120 by 8. 120 divided by 8 is 15. So it will take 15 days collecting 8 cards a day in order to reach the 120 cards he still needs to collect.
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HELP ME ASAP HELP ME ASAP HELP ME ASAP
Anon25 [30]

Answer:

First, plot the y-intercept. The y-intercept is 1, so plot the point (0,1).

Then go up 2 points and to the right 3 points and plot a point there. (3,3)

We go to the right because the slope is positive.

Draw a line through the two points.

Step-by-step explanation:

y = mx+b

m = slope

b = y-intercept

8 0
2 years ago
You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
ASHA 777 [7]

Answer:

a

  Yes

b

 P(1 \& 5) = \frac{1}{36}

c

 P(5 \& 1) = \frac{1}{36}

d

 P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

Step-by-step explanation:

From the question we are told that

     Two fair dice, one green and one red were rolled

Generally the  outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the  probability of getting a 1  on a dice rolled is  P(1) =  \frac{1}{6}

the  probability of getting a 5 on a dice rolled is  P(5) =  \frac{1}{6}

Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

         P(1 \& 5) = \frac{1}{6}  *\frac{1}{6}

         P(1 \& 5) = \frac{1}{36}

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

          P(5 \& 1) = \frac{1}{6}  *\frac{1}{6}

         P(5 \& 1) = \frac{1}{36}

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

          P(5 \& 1 | 1\& 5  ) = \frac{1}{36} + \frac{1}{36}

         P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

8 0
2 years ago
Suppose a basketball player has made 390 out of 434 free throws. If the player makes the next 2 free throws, I will pay you $40.
alukav5142 [94]

Answer: a) -$0.19, b) -$111.72 .

Step-by-step explanation:

Since we have given that

Number of free throws = 434

Number of throws made by them = 390

Amount for making the next 2 free throws = $40

Amount otherwise he has to pay = $169

a) Find the expected value of the proposition.

Expected value of success in next 2 free throws = \dfrac{390}{434}\times \dfrac{391}{435}=0.8077

Expected value would be

0.8077\times 40+(1-0.8077)\times -169\\\\=32.308-32.4987\\\\=-\$0.19

b)  If you played this game 588 times how much would you expect to win or lose?

Number of times they played the game = 588

So, Expected value would be

588\times -0.19\\\\=-\$111.72

Hence, a) -$0.19, b) -$111.72

8 0
3 years ago
NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS ONLY PLZ WILL REPORT FAKE ANSWERS
Contact [7]

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive terms

r = 24 ÷ 16 = 36 ÷ 24 = 54 ÷ 36 = 1.5 = \frac{3}{2}

This indicates the sequence is geometric with nth term ( explicit formula )

f(n) = a₁(r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 16 and r = \frac{3}{2} , then

f(n) = 16 (\frac{3}{2}) ^{n-1} → C

6 0
2 years ago
What if i had 2 ducks and add 4 more​
Travka [436]

Answer:

You would have 6 ducks

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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