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2 years ago

HeLp! I need HeLp! Plz hElP! ThAnK YoU!

Mathematics

1 answer:

marin [14]2 years ago

6 0

X=84° because the 84 above it and x are corresponding angles

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Given rectangle QUAD, if QU = 13, find DA.

lora16 [44]

Step-by-step explanation:

DA=13.................

6 0

2 years ago

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cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

2 years ago

Estimate the original volume of the pyramid in Fig. 15.28, given that its frustum has a 4 m by 4 m square top which is 12 m vert

puteri [66]

The volume of the pyramid is 2496 cu.m.

<h3>What is a Pyramid ?</h3>

A pyramid is a three dimensional structure which has a polygon base and in general triangular faces which join at the top .

It is given that

A pyramid $\rm frustum$ has a 4 m by 4 m square top

Height = 12 m

Base = 20 m

The volume of a square pyramid with a $\rm frustum$ is given by

V = (1/2) * ( Area of base + Area of $\rm frustum$ ) * height of the $\rm frustum$ from the base

V = 0.5 * ( 20 *20 + 4*4 ) * 12

V = 2496 cu.m

The volume of the pyramid is 2496 cu.m.

To know more about Pyramid

brainly.com/question/13057463

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8 0

2 years ago

Help me answer correctly !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

mrs_skeptik [129]

Show the question so I can answer it for you.

6 0

2 years ago

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A rectangular prism with a volume of 10 cubic units is filled with cubes with side lengths of 1/2

Katarina [22]

The answer is 5 Bc it’s half of ten

7 0

3 years ago