Ask question

Ask question

All categories

3 years ago

7

Find the sum: –1.54 + 5.093 ...?

2 answers:

Dvinal [7]3 years ago

7 0

3.553 use a calculator

fgiga [73]3 years ago

4 0

The answer is 3.553. Since -1.54 is lacking the thousandth's part, insert 0 in it to match the 5.093 thus arriving at the equation -1.540 +5.093 = x. Then sum it up. you'll arrive at the answer 3.553, with the positive sign because of 5.093 is greater than 1.54

You might be interested in

Write the first expression in terms of the second if the terminal point determined by t is in the given quadrant.

Vesnalui [34]

Answer:

Step-by-step explanation:hhhhyg

8 0

2 years ago

What is the sum of the first 6 terms of this geometric sequence? –4, –16, –64, –256, …

MatroZZZ [7]

$a_1=-4;\ a_2=-16;\ a_3=-64;\ a_4=-256;\ ...\\\\r=\dfrac{a_{n+1}}{a_n}\to r=\dfrac{a_2}{a_1}\to r=\dfrac{-16}{-4}=4$

The formula of the sum of a geometric sequence:

$S_n=a_1\cdot\dfrac{1-r^n}{1-r}$

We have:

$a_1=-4;\ n=6;\ r=4$

substitute:

$S_6=-4\cdot\dfrac{1-4^6}{1-4}=-4\cdot\dfrac{1-4096}{-3}=-4\cdot\dfrac{-4095}{-3}=-4\cdot1365=-5460$

Answer: C. -5460

6 0

3 years ago

Write the numbers in the blanks that make this equation true.<br><br> ( 2 + 1 ) + 3 = 2 + ( _ + _ )

Marta_Voda [28]

(2+1)+3=2+(2+2)

Any two numbers that add to 4.

7 0

1 year ago

Find the value of x. Write your answer in simplest form.

Brilliant_brown [7]

Answer:

by using Pythagoras theorm

${x}^{2} + {x}^{2} = {(9 \sqrt{2)} }^{2} \\ 2 {x}^{2} = 81 \times 2 \\ 2 {x}^{2} = 162 \\ {x}^{2} = 81 \\ x = \sqrt{81} \\ x = 9$

Step-by-step explanation:

<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>

4 0

3 years ago

Read 2 more answers

On a family outing, Tyler bought 5 cups of hot cocoa and 4 pretzels for $18.40. Some of his family

elena55 [62]

Answer:

hindi ko po gits malay mo po sa iba mo po ma lalaman ang sagut

5 0

2 years ago