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Musya8 [376]
3 years ago
13

A capacitor with plates separated by a distance d is charged to a potential difference ΔVC. All wires and batteries are disconne

cted, then the two plates are pulled further apart to a new separation distance 2d. What happens to the potential difference across the capacitor, ΔV, and the charge on the capacitor, Q, as a result of this change?
Physics
1 answer:
Tom [10]3 years ago
6 0

Answer:

Explanation:

Initial separation of plate = d

final separation = 2d

The capacitance of the capacitor will reduce from C to C/2 because

capacitance = ε A / d

d is distance between plates.

As the batteries are disconnected , charge on the capacitor becomes fixed .

Initial charge on the capacitor

= Capacitance x potential difference

Q = C ΔV

Final charge will remain unchanged

Final charge = C ΔV

Final capacitance = C/2

Final potential difference = charge / capacitance

= C ΔV /  C/2

= 2 ΔV

Potential difference is doubled after the pates are further separated.

You might be interested in
10. Calculate the kinetic energy of a running back that has a mass of 80 kg and
EastWind [94]

Answer:

The answer is

<h2>2560 J</h2>

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}

where

m is the mass

v is the velocity

From the question

m = 80 kg

v = 8 m/s

The kinetic energy is

KE =  \frac{1}{2}  \times 80 \times  {8}^{2}  \\  = 40 \times 64

We have the final answer as

<h3>2560 J</h3>

Hope this helps you

5 0
3 years ago
A skateboarder skates down a ramp for 3 seconds. If his initial velocity was 0.8 m/s and · his final velocity was 7 m/s, what wa
Contact [7]

Answer:

The acceleration of the skateboarder is 2.067 m/s²

Explanation:

Given;

initial velocity of the  skateboarder, u = 0.8 m/s

final velocity of the  skateboarder, v = 7 m/s

time of motion, t = 3 s

The acceleration of the skateboarder is given as;

a = \frac{v-u}{t}\\\\a = \frac{7-0.8}{3}\\\\a = 2.067   \ m/s^2

Therefore, the acceleration of the skateboarder is 2.067 m/s²

5 0
3 years ago
When the batter hit the foul ball, the baseball moved upward to a delighted fan in the top deck.
oee [108]

Answer:

B) Kinetic energy increases, potential energy decreases

Explanation:

In a given system, when a body is at rest, v =0m/s, the kinetic energy is at zero while the potential energy is at maximum. However, when a body is in motion with a velocity = v, the potential energy is at zero while the kinetic energy is at maximum.

Before this happen, the a body at rest (P.E = max) is set on motion, the kinetic energy gradually increases till it converts all the potential energy in the system to kinetic energy and then reverses back when the body goes to rest again.

In this case, before the batter hits the ball, the kinetic energy was at zero while the potential energy was at maximum. However, when he hits the ball and sets it into motion with a velocity V, the potential energy converts to kinetic energy and moves the ball with that energy till it has expanded it and comes to rest.

Potential Energy → Kinetic Energy → Potential Energy.

That's how the system keeps changing.

6 0
3 years ago
A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of
AveGali [126]

The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

f_g=\frac{1}{r^2}

where

f_g is the gravitational force

r^2 is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore \frac{1}{4} \times400 = 100N

3 0
3 years ago
100g converted to kg .
natka813 [3]

Answer: 0.1 kilogram

4 0
3 years ago
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