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kiruha [24]
3 years ago
15

What tools can you use for measuring mass?

Physics
2 answers:
Sedbober [7]3 years ago
6 0

Answer:

ruler:(

Explanation:

?

iren [92.7K]3 years ago
3 0

Answer:

With a balance

Explanation:

Such as an electronic balance and a triple beam balance

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-Cesar the monkey observed the swinging behaviors of his parents. He is now able to swing from branch to branch after much pract
alexgriva [62]

The 3rd one I think . I did something similar a while ago
4 0
4 years ago
What does it mean when we say two objects are in equilibrium
cupoosta [38]

An object is considered to be in a condition of equilibrium when it is balanced with regard to all external forces.

Equilibrium:

An object is considered to be in equilibrium if both its angular acceleration and the acceleration of its center of mass are equal to zero. In layman's terms: The item must either be at rest or moving at a constant speed if it is not accelerating because F = ma (force = mass x acceleration). Even in motion, a body can be in equilibrium. This kind of equilibrium is referred to as a dynamic equilibrium.

A weight suspended by a spring or a brick laying on a flat surface is an example. The equilibrium is unstable if the force with the smallest deviation tends to increase the displacement. As an example, imagine a ball bearing on the edge of a razor blade.

Learn more about equilibrium here:

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8 0
2 years ago
You place a large pebble in a slingshot, pull the elastic band back to your chin, and release it, launching the pebble horizonta
sladkih [1.3K]

Answer:

The larger pebble has 25 times more mass.

Explanation:

To solve the exercise it is necessary to apply the work and energy conservation equations.

For the case described, the work done must be preserved and must be the same, that is,

W = 0

By definition work linked to the conservation of kinetic energy would be given by

\Delta KE = W = 0

\Delta KE = 0

KE_{larger}-KE_{smaller} = 0

KE_{larger}=KE_{smaller}

\frac{1}{2}m_lv_l^2 = \frac{1}{2}m_sv_s^2

m_lv_l^2 = m_sv_s^2

The ratio between the mass and the velocity would be,

\frac{m_l}{m_s}=\frac{v_s^2}{v_l^2}

\frac{m_l}{m_s} = \frac{500^2}{100^2}

\frac{m_l}{m_s} = 25

Therefore the answer is: The larger pebble has 25 times more mass.

4 0
3 years ago
In Part I, the independent variable, the one that is intentionally manipulated, is blank.
Feliz [49]

Answer: part 1 is mass and part 2 is density

Explanation: I just did it and got it right

6 0
3 years ago
Read 2 more answers
Now imagine a person dragging a 50 kg box along the ground with a rope, as
ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

                                                     = 50 x 9.8

                                                     = 490 N

The coefficient of friction,

                            μ = f/ η

                               = 30 / 490

                               = 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0
4 years ago
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