Answer:
173.75 km/hr in the NW direction.
Explanation:
Velocity is the time rate of change in displacement of a body. Mathematically:
v = d / t
where d = displacement
t = time
Therefore, the velocity of the car is:
v = 556 / 3.2 = 173.75 km/hr
The velocity of the car is 173.75 km/hr in the NW direction.
(a) 6.04 rev/s
The speed of the ball is given by:
where
is the angular speed
r is the distance of the ball from the centre of the circle
In situation 1), we have
r = 0.600 m
So the speed of the ball is
In situation 2), we have
r = 0.900 m
So the speed of the ball is
So, the ball has greater speed when rotating at 6.04 rev/s.
(b) 
The centripetal acceleration of the ball is given by
where
v is the speed
r is the distance of the ball from the centre of the trajectory
For situation 1),
v = 30.6 m/s
r = 0.600 m
So the centripetal acceleration is
(c) 
For situation 2 we have
v = 34.1 m/s
r = 0.900 m
So the centripetal acceleration is
Answer:
5,865,696,000,000
Explanation:
31,536,000 seconds in a year. 31,536,000×186,000=5,865,696,000,000
Answer:
Explanation:
a ) V( primary ) = 100 V
V( secondary ) = 10 V
No of turns ( secondary ) / No of turns ( primary ) = 10 / 100
= 1 / 10
b ) current in secondary
= volt ( secondary ) / resistance
= 10 /6 = 1.67 A
c )
Average power to secondary
= V ( secondary ) x current ( secondary )
= 10 x 10 / 6
= 16.67 W
d )
Power in primary = power in secondary = 16.67 W
e ) current drawn by ac line ( primary )
Volt ( primary ) x current ( primary ) = power in primary
= 16.67
current ( primary )
= 16.67 / 100
= 0.167 A
a)
Y₀ = initial position of the stone at the time of launch = 0 m
Y = final position of stone = 20.0 meters
a = acceleration = - 9.8 m/s²
v₀ = initial speed of stone at the time of launch = 30.0 m/s
v = final speed = ?
Using the equation
v² = v₀² + 2 a (Y - Y₀)
inserting the values
v² = 30² + 2 (- 9.8) (20 - 0)
v = 22.5 m/s
b)
Y₀ = initial position of the stone at the time of launch = 0 m
Y = maximum height gained
a = acceleration = - 9.8 m/s²
v₀ = initial speed of stone at the time of launch = 30.0 m/s
v = final speed = 0 m/s
Using the equation
v² = v₀² + 2 a (Y - Y₀)
inserting the values
0² = 30² + 2 (- 9.8) (Y - 0)
Y = 46 m
