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Elis [28]
3 years ago
10

Determine whether the points lie on straight line.

Mathematics
1 answer:
wel3 years ago
6 0

Answer:

A) Non-collinear- does not lies on straight line

B) Collinear- lie on straight line

Step-by-step explanation:

We have to check collinearity of three points.

The points (x_1, y_1, z_1),(x_2, y_2, z_2),(x_3, y_3, z_3) are said to be collinear if,

\left[\begin{array}{ccc}x_1&y_1&z_1\\x_2&y_2&z_2\\x_3&y_3&z_3\end{array}\right] = 0

A) A(2, 5, 3), B(3, 7, 1), C(1, 4, 4)

\left[\begin{array}{ccc}2&5&3\\3&7&1\\1&4&4\end{array}\right] \\\\=2(28-4)-5(12-1)+3(12-7)\\= 8 \neq 0

Thus, the given points are not collinear.

B) D(0,-5,5), E(1,-2,4), F(3,4,2)

\left[\begin{array}{ccc}0&-5&5\\1&-2&4\\3&4&2\end{array}\right] \\\\=0(-4-16)+5(2-12)+5(4+6)\\=0

Thus, the given points are collinear.

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Step-by-step explanation:

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In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.
Inga [223]

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

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BH⊥ AC

AB=AC=4

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madreJ [45]

<u><em>Answer:</em></u>

Her hourly rate is $8.25

<u><em>Explanation:</em></u>

Tatianna works 3 hours a day on school days and makes a total of $123.75 in a week

<u>We know that:</u>

There are 5 school days in a week

<u>We are given that:</u>

She works for 3 hours a day each of those days

<u>Therefore:</u>

Total number of hours worked = hours worked daily * number of days

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<u>The equation used to calculate Tatianna's earnings is:</u>

Amount she makes in a week = Total number of hours worked * hourly rate

<u>Now, we substitute with the givens to get the hourly rate as follows:</u>

Amount she makes in a week = Total number of hours worked * hourly rate

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The answer is 94.50 so C. I hope this helped. :)
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