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9966 [12]
3 years ago
8

Which matrix does not have an inverse

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

Doesnt Have a matrix its singular I believe, But I can really help on that

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A family of four is trying to determine what they want to do for their summer vacation and came up with three options. They have
Nikolay [14]
Option 1 =$497.5 option 2 =$494.5 option 3 =$50.5
8 0
3 years ago
Wendy saved up for a family trip to the beach. For each $1 she saved, her parents pledged to save $5. If her parents were able t
viva [34]
225/5 = 45
This means the parents gave her five dollars forty five times. If they gave her a five every time she saved one dollar, you just have to multiply the money she saved each time and the number of times she saved it, and you'll get the answer. 
Wendy saved $45 by herself
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3 years ago
Read 2 more answers
A=8b+c solve for b <br> Please help!
balu736 [363]

Answer:

(A-c)/8 = b

Step-by-step explanation:

A = 8b +c

A - c = b

(A-c)/8 = b

Hope this helps you!

3 0
3 years ago
Investigate the existence of a extrema value, what does the markered part mean?
OLga [1]

Answer: We have

f'(x) = a x + b,

f'(x) = 0 at x = -b/a

f(x) = a x^2 / 2 + b x + c


Meaning of marked part


❟ ∵ a<0 ❟ f is a quadratic function

∴ f has absolute maximum value at x = -b/a


For all a with a less than zero, f is a quadratic function. Therefore f has a global maximum at x = -b/a


That typesetting seems very sloppy. It probably is supposed to be


∀a < 0, f is a quadratic function.


The second sentence is sloppy in use of "absolute". It can't mean absolute value, so presumably it means "global".


Sometimes a minimum or maximum is only local, but a quadratic function has exactly one extrema, and it is global. And if a < 0, the extrema is a global maximum.


Step-by-step explanation:


An extrema (minimum or maximum) for f(x) occurs only where f'(x) = 0, that is, when the slope of the tangent at x is zero.


But if the function crosses its tangent at that point, the point is an inflection point, not an extrema. A quadratic never crosses it's tangent.


5 0
3 years ago
Given directed line segment AB determine point X on the graph such that X partions the segment A to B in a ratio of 1:4 and give
Viktor [21]

Answer:

The coordinates of point X that divides the line in 1:4 are: (3,8/5)

Step-by-step explanation:

When a point divides a line with coordinates (x1,y1) and (x2,y2) in ratio m:n,

the coordinates of point are given by:

(x,y) = (\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n})

Given points are:

(x1,y1) = (5,1)

(x2,y2) = (-5,4)

Putting the values in the formula

X(x,y) = (\frac{(1)(-5)+(4)(5)}{1+4} , \frac{(1)(4)+(4)(1)}{1+4})\\= (\frac{-5+20}{5}, \frac{4+4}{5})\\=(\frac{15}{5}, \frac{8}{5})\\=(3,\frac{8}{5})

Hence,

The coordinates of point X that divides the line in 1:4 are: (3,8/5)

8 0
3 years ago
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