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3 years ago

Please help!! Will give brainliest

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

4 0

Answer:

b) 16 rt 2

Step-by-step explanation:

using the 45-45-90 triangle trick,

let x=16

then BC is x rt 2, or 16 rt 2

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Step-by-step explanation:

6 0

3 years ago

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What is the solution to the equation StartFraction 3 Over m + 3 EndFraction minus StartFraction m Over 3 minus m EndFraction = S

Oksanka [162]

Answer:

No solution.

Step-by-step explanation:

Given fraction is:

$\dfrac{3}{m+3} -\dfrac{m}{3-m} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3}{m+3} +\dfrac{m}{m-3} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3\times (m-3)+ m(m+3)}{(m+3)(m-3)} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3 m-9+ m^2+3m}{m^2-9} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{m^2-9+ 6m}{m^2-9} = \dfrac{m^2+9}{m^2-9}\\If\ m^2-9 \neq 0\ or\ m \neq 3\\\Rightarrow m^2-9+ 6m = m^2+9\\\Rightarrow 6m = 18\\\Rightarrow m = 3$

Formula used:

$(a+b)(a-b) = a^{2} -b^{2}$

But, the above equation was solved at the condition that:

$m\neq 3$

So, there is no solution for the given equation.

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3 years ago

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