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Elis [28]
2 years ago
14

-6-4+[-4] 0 [-4-[-3]] [4² + 3²] ÷ 5

Mathematics
1 answer:
mestny [16]2 years ago
7 0

Answer:

you can eat this panipuri then you will got answer

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Let E be the event that a corn crop has an infestation of ear worms, and let B be the event that a corn crop has an infestation
KatRina [158]

Answer:

The probability that a corn crop has either an ear worm infestation, a corn borer infestation

P(EUB) = 0.27

Step-by-step explanation:

<u>Explanation</u>:-

<u>Addition theorem on probability</u>:-

If S is a sample space, and E , F are any events in S then

P(EUF) = P(E) +P(F) -P(E n F)

Let 'E' be the event that a corn crop has an infestation of ear worms

let 'B' be the event that a corn crop has an infestation of corn bores

P(EUB) = P(E) +P(B) -P(E n B)

given P(E) = 0.24 and P(B) = 0.16 and P(E n B) =0.13

P(EUB) = P(E) +P(B) -P(E n B)

P(EUB) = 0.24 + 0.16 - 0.13

           = 0.27

The probability that a corn crop has either an ear worm infestation, a corn borer infestation

P(EUB)=0.27

7 0
3 years ago
The midpoint of AB is M(-3, 0). If the coordinates of A are (1,-4), what are the coordinates of B?
zimovet [89]

Using the given information, the coordinates of B are (-7, 4)

<h3>Midpoint of a Line </h3>

From the question, we are to determine the coordinates of B.

Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is

((x₁+x₂)/2, (y₁+y₂)/2)

From the given information,

The midpoint of AB is M(-3, 0)

and

The coordinates of A are (1,-4)

Let the coordinates of B be (x₁, y₁)

Then,

-3 = (1 + x₁)/2

-6 = 1 + x₁

x₁ = -6 -1

x₁ = -7

Also,

0 = (-4 + y₁)/2

0 = -4 + y₁

y₁ = 0 + 4

y₁ = 4

Hence, the coordinates of B are (-7, 4)

Learn more on Midpoint of a line here: brainly.com/question/18315903

#SPJ1

7 0
1 year ago
Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 1818 cans of the
ohaa [14]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 18 cans of the soda drink. Those volumes have a mean of 12.19 oz and a standard deviation of 0.14 oz, and they appear to be from a normally distributed population.

If the workers want the filling process to work so that almost all cans have volumes between 12.02 oz and 12.66 ​oz, the range rule of thumb can be used to estimate that the standard deviation should be less than 0.16 oz. Use the sample data to test the claim that the population of volumes has a standard deviation less than 0.16 oz. Use a 0.01 significance level. Complete parts​ (a) through​ (d) below.

a. Identify the null and alternative hypotheses.  

b. Compute the test statistic.

c. Find the p-value.

d. State the conclusion.

Answer:

Null hypotheses = H₀: σ = 0.16  oz

Alternate hypotheses = H₁: σ < 0.16  oz

Critical value = 6.408

Chi-square value = \chi^2 = 13.016

Reject H₀  Since \chi^2 > Critical value

Reject H₀ Since p-value ≤ α

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

Step-by-step explanation:

Set up hypotheses:

The null hypotheses is that the population of volumes has a standard deviation of 0.16 oz

Null hypotheses = H₀: σ = 0.16  oz

The claim to be tested is that the population of volumes has a standard deviation of less than 0.16 oz

Alternate hypotheses = H₁: σ < 0.16  oz

Determine type of test:

Since the alternate hypothesis states that the population of volumes has a standard deviation of less than 0.16 oz, therefore we will use a lower-tailed chi-square test.

Determine the Critical value:

Given level of significance = 0.01

Since it is a lower-tailed test, the areas given in the chi-square table are the areas to the right of the critical value. To get the areas on the left, subtract it from  one, and then look it up

α = 1 - 0.01 = 0.99

degree of freedom = df = n - 1 = 18 - 1 = 17

The critical value from the chi-square table at α = 0.99 and df = 17 is found to be

Critical value = 6.408

Using an online “chi-square p-value calculator”

The left tail p-value for df = 17 and Critical value = 6.408 is found to be

p-value = 0.01

Set up decision rule:

Reject H₀ If  > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

OR

Reject H₀ If p-value ≤ α

Compute the test statistic:

$ \chi^2 = \frac{(n-1) s^2}{\sigma^2} } $

$ \chi^2 = \frac{(18-1) 0.14^2}{0.16^2} } $

\chi^2 = 13.016

Conclusion:

We reject H₀

Since \chi^2 > Critical value

13.016 > 6.408

Also

p-value ≤ α

0.01 ≤ 0.01

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

5 0
2 years ago
When measuring distance 43 peas are approximately equal to 19 beans. How many peas are equal to 133 beans?
nikdorinn [45]

Answer:

  301

Step-by-step explanation:

Assuming the proportion holds over longer distances, the ratios can be written ...

  peas/beans = p/133 = 43/19

  p = 133(43/19) = 301

301 peas are equal to 133 beans.

4 0
2 years ago
3(h - 7) + 3 = 9 what is H =
MrRissso [65]

Answer:

9

Step-by-step explanation:

3(h-7)+3=9

3h-21+3=9

3h-18=9

3h=9+18

3h=27

h=27/3

h=9

Please mark me as Brainliest if you're satisfied with the answer.

7 0
2 years ago
Read 2 more answers
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