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tiny-mole [99]
3 years ago
11

Aiden works at a garden center where he pots plants. It takes him 2 1/2 hours to pot 15 plants. How many plants can Aiden pot in

1 hour? (I need help please. This is for 15 points. Thanks)
Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

6\ plants

Step-by-step explanation:

Remember that

2\frac{1}{2}\ hours=\frac{5}{2}\ hours

Using proportion

\frac{15}{(5/2)}\frac{plants}{hours} =\frac{x}{1}\frac{plants}{hour}\\ \\x=15*2/5\\ \\x=6\ plants

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MZJ and m M are base angles of isosceles trapezoid JKLM. If mZJ = 18x + 8 and m_M=11x + 15 find m2K.
maxonik [38]

The question is incomplete. Here is the complete question.

m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.

If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.

A. 1

B. 154

C. 77

D. 26

Answer: B. m∠K = 154

Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.

Related to internal angles, angles of the base are equal and opposite angles are supplementary.

In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:

18x + 8 = 11x + 15

7x = 7

x = 1

Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:

m∠J = 18(1) + 8

m∠J = 26

m∠K + m∠J = 180

m∠K + 26 = 180

m∠K = 154

The angle m∠K is 154°

7 0
3 years ago
The lengths of a particular snake are approximately normally distributed with a given mean mu = 15 in. and standard deviation si
Helga [31]

The percentage of the snakes is longer than 16.6 in. with a mean of 15 in. and a standard deviation of 0.8 in. is 2.275%.

<h3>What is a normal distribution?</h3>

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and standard deviation = 0.8 in.

Then the percentage of the snakes is longer than 16.6 in. will be

z = \dfrac{ x - \mu }{ \sigma }\\\\z = \dfrac{16.6-15}{0.8}\\\\z = 2

Then we have

\rm P(x > 16.6) = P(z > 2) = 0.02275  \ or  \ 2.275 \%

More about the normal distribution link is given below.

brainly.com/question/12421652

6 0
2 years ago
What is the final cost of a $21,000 car with a sales tax of 7%?
fomenos
21,000 + 0.07(21,000) = 21,000 + 1,470 = 22,470
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