I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such
anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent
(oposite side=side oposite the angle
adjacent is the side touching the angle that is not they hypotonuse
and of course the hypotonuse is the longest side aka, side oposite right angle)
6/24=1/4=25%
answer is 25% are bad
Answer:
Part a) The area of the swimming pool is 
Part b) The total area of the swimming pool and the playground is 
Step-by-step explanation:
Part a) Find the area of the swimming pool
we know that
The area of the swimming pool is

where
L is the length side
W is the width side
we have

substitute the values


therefore
The area of the swimming pool is 
Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground
we know that
To obtain the area of the playground multiply the area of the swimming pool by one and a half

To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground
so

therefore
The total area of the swimming pool and the playground is 
Answer:
C is the answer
Step-by-step explanation:
The domain can't be minus. That's the only stipulation. It can be equal to 0 or anything larger than 0. It just can't go into the minus numbers.
0≤x<infinity.
C