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kondor19780726 [428]
3 years ago
7

If vector v has an initial point at P1 and a terminal point at P2, write v as multiples of the basis vectors That is, write v in

the form v = ai + bj.
P1 = (−5, −2), P2 = (4, 1) and v = ?
Mathematics
1 answer:
pantera1 [17]3 years ago
8 0

Answer:

v=9i+3j

Step-by-step explanation:

The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).

The vector v is found by subtraction the initial point from the terminal point.

v=<4,1>-<-5,-2>

v=<4--5,1--2>

v=<9,3>

We write v as multiples of the basis vectors to obtain:

v=9i+3j

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If integer k is equal to the sum of all even multiples of 15 between 295 and 615, what is the greatest prime factor of k?
ohaa [14]

Answer:

The greatest prime factor of k is 11.

Step-by-step explanation:

∵  LCM( 2, 15) = 30,

Thus, the even multiple of 15 must be multiple of 30,

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300, 330, 360,..........600

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Common difference, d = 30,

If n be the number terms,

Last term = a+(n-1)d

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=270 + 30n

\implies 270+30n = 600\implies 30n = 330\implies n = 11

Hence, the sum of the all even multiple of 15 from 295 to 615,

S_{11}=\frac{11}{2}(2(300)+(11-1)30)=\frac{11}{2}(600+300)=\frac{11}{2}(900)=11\times 450

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