Answer:
v=9i+3j
Step-by-step explanation:
The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).
The vector v is found by subtraction the initial point from the terminal point.
v=<4,1>-<-5,-2>
v=<4--5,1--2>
v=<9,3>
We write v as multiples of the basis vectors to obtain:
doyy7p57ediyfir7esusyig868surzydgkhipoti8tuiyi6ryi5iyruruoyripitsyrahfzofuuts
1. y = (-4^3)^2
2. y= 2^4/ 6^2
8/23. Sana po makatulong