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weeeeeb [17]
3 years ago
8

PLEASEEEEEEEEEEEEEE HELPPPPPPP PLEASEEEEEE !!!!

Mathematics
2 answers:
shusha [124]3 years ago
7 0

Answer:

x=\frac{\sqrt{2}}{2}

Step-by-step explanation:

The given triangle is an isosceles right triangle, meaning that the 45-45-90 triangle side rule applies. The 45-45-90 triangle side rule states that the two legs (sides that are adjacent to the right angle) are congruent, and the hypotenuse (the side opposite the rights angle) is equal to the leg times the square root of two. Using this property, one knows that the leg is equal to the hypotenuse divided by the square root of two. In this problem, the hypotenuse is equal to (1), and the leg is equal to (x). Therefore, one can say,

x = \frac{1}{\sqrt{2}}

Rationalize the denominator,

\frac{1}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}\\\\\frac{\sqrt{2}}{2}

Maurinko [17]3 years ago
3 0

Answer:

Step-by-step explanation:

a² + b²  = c²     look familiar?  it is the Pythagorean theorem

both side are the same length since both angles are the same some sort of Isosceles triangle rule I think    so side 1 = x   side 2 = x and  hypotenuse = 1

x² + x²  = 1²

   2x²   = 1

     x²   = 1/2

     x     =     √(1/2)      the denominator is  NOT rational in this FORM

     x    =    √1 / √2       multiple the numerator and the denominator by √2

     x    =    1 (√2) / (√2)(√2)

     x    =   √2 / √2²

     x    =   √2 / 2        finding a rational denominators means nothing

                                  just do more work and more typing for me,

                                  a silly MATH rule

   

  x = √2/2   =  0.7071        x = √(1/2)  = √(0.5)   =  0.7071   the SAME Number

 sorry, my rant of the day

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Step-by-step explanation:

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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

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ii.

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Step-by-step explanation:

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G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

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1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

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Solving (bi) At least 2 are girls

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Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

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P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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