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4 years ago

HELP ME PLZ !!! The first one who answers gets brainliest

Mathematics

2 answers:

Snowcat [4.5K]4 years ago

5 0

Believe the answer is the second one, 7

elena-14-01-66 [18.8K]4 years ago

5 0

Ans: NONE

Hope this can help.

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Perform the multiplication:

LUCKY_DIMON [66]

First one is 33y^3-22y^2-27y+18
Second one is -3a^4-20a^2 x^2+7x^4
I hope this helps you :)

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4 years ago

Fredy and his friends went to a basketball game. Fredy decided to buy refreshments for everyone. He bought hot dogs, which cost

antiseptic1488 [7]

Answer:

Step-by-step explanation:

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3 years ago

During a thunderstorm yesterday, 600 millimeters of rain fell in 30 minutes. What is the unit rate for millimeters per minute?

eimsori [14]

Answer:

.33

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x2/(x4 +

ella [17]

Answer:

Given the function: $f(x) =\frac{x^2}{x^4+16}$

A geometric series is of the form of :

$\sum_{n=0}^{\infty} ar^n$

Now, rewrite the given function in the form of $\frac{a}{1-r}$ so that we can express the representation as a geometric series.

$\frac{x^2}{x^4+16}$

Now, divide numerator and denominator by $x^4$ we get;

$\frac{\frac{1}{x^2}}{1+\frac{16}{x^4}}$ = $\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2}$

Therefore, we now depend on the geometric series which is;

$\frac{1}{1+x} =\sum_{n=0}^{\infty} (-1)^n x^n$

let $x \rightarrow x^2$ then,

$\frac{1}{1+x^2} =\sum_{n=0}^{\infty} (-1)^n x^{2n}$

to get the power series let $x \rightarrow \frac{4}{x^2}$

so,

$\frac{1}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

Multiply both side by $\frac{1}{x^2}$ we get;

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\frac{1}{x^2} \cdot \sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =x^{-2} \cdot \sum_{n=0}^{\infty} (-1)^n (16)^n (x^{-2})^{2n}$

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n} \cdot x^{-2}$

Using $x^n \cdot x^m = x^{n+m}$

we have,

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

therefore, the power series representation centered at x =0 for the given function is: $\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

6 0

3 years ago

Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Ishaan now?

MrRissso [65]

I= Ishaan's age= 2C
C= Christopher's age

35 years ago means we have to subtract 35 from their current age. Ishaan minus 35 equals 7 times Christopher minus 35 years.

CHRISTOPHER'S AGE:
I - 35= 7(C-35)
substitute I=2C in for I
multiply 7 by all in parenthesis

2C - 35= 7C - 245

add 35 to both sides
2C= 7C - 210

subtract 7C from both sides
-5C = -210

divide both sides by -5

C= 42 Christopher's age

ISHAAN'S AGE:
I= 2C
substitute C=42 to find Ishaan's age
I= 2(42)

I= 84 Ishaan's age

CHECK:
Substitute answers in original equation

I - 35= 7(C-35)
84 - 35= 7(42-35)
49= (7*42)+(7*-35)
49= 294-245
49=49

Hope this helps! :)

6 0

3 years ago