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Aneli [31]
3 years ago
11

For each store what is the ratio of cans to price

Mathematics
1 answer:
irinina [24]3 years ago
7 0
What is the amount of cans so i can answer
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If 2^2x = 2^3, what is the value of x?
Advocard [28]

Answer:

x=3/2

Step-by-step explanation:

2^2x=2^3

2x=3

x=3/2

6 0
3 years ago
Melinda bought 6 bowls for $13.20. what was the unit rate in dollars
never [62]
<u>6
</u>13.20
Divide by 6
<u>1
</u>2.2
6 0
3 years ago
What is the minimum and maximum of f(x)=-10x^3+6x-2
const2013 [10]

Answer:

Minimum: (\frac{\sqrt{5} }{5},-2+\frac{4\sqrt{5}  }{5})

Maximum: (-\frac{\sqrt{5} }{5} ,-2-\frac{4\sqrt{5} }{5} )

Step-by-step explanation:

5 0
3 years ago
The quotient of a number j and 3 is 5
masha68 [24]

Answer:

j = 15

Step-by-step explanation:

\frac{j}{3} =5\\3*\frac{j}{3} =5*3\\j=15

5 0
3 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
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