We can break down the number 6647 into:
6647=6000+600+40+7
The first 6 in the number is in the thousands place (6,000), and the second 6 is in the hundreds place (600).
The first 6 is 10 times greater than the second one.
Can you be more specific? I need a question and I need a close up ! Lol but I’m trying to help.
A quadratic equation is in the form of ax²+bx+c. The time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.
<h3>What is a quadratic equation?</h3>
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.
The complete question is:
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) after 7 seconds is given by the following, h=2+31t-16t². Find all values of t for which the ball's height is 16 feet. Round your answer(s) to the nearest hundredth.
The time at which the height of the ball is 16 feet can be found by,
h = 2 + 31t - 16t²
16 = 2 + 31t - 16t²
16 - 2 - 31t + 16t² = 0
16t² - 31t + 14 = 0

t = 0.717 , 1.221
Hence, the time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.
Learn more about Quadratic Equations:
brainly.com/question/2263981
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Answer:
T = 88 degrees to the nearest degree
Step-by-step explanation:
To find the measure of the angle T, we can use the cosine rule
We have the formula as;
t^2 = u^2 + v^2 - 2uv Cos T
t = 8.1
u = 7.1
v = 4.2
8.1^2 = 7.1^2 + 4.2^2 - 2(7.1)(4.2) cos T
-2.44 = -59.64 cos T
cos T = (2.44)/(59.64)
T = arc cos (2.44/59.64)
T = 87.66
to the nearest degree, this is 88 degrees
Answer:
110.4
Step-by-step explanation: