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2 years ago

2x+3y=6 x+2y=5 solve using multiplication

Mathematics

1 answer:

katrin [286]2 years ago

8 0

In this set of equations, x is -3 and y is 4.

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Help please!

Charra [1.4K]

Answer:

Step-by-step explanation:

The period is the x distance for one full cycle.

The 1st peak is at 1 and the second peak at 15

The period is 15 - 1 = 14

5 0

2 years ago

HEEEEEELLLLLLLPPPPP !!!!!!!!!

ludmilkaskok [199]

Calculate the length of each path using the law of cosines:

AB = √(8^2 + 8^2 - 2*8*8*cos(36)

AB = 4.94 ft.

XY = √(8^2 + 8^2 - 2*8*8*cos(79)

XY = 10.18 ft.

ZY = √(8^2 + 8^2 - 2*8*8*cos(65)

ZY = 8.60 ft.

XY is longer than ZY and ZY is longer than AB

The first choice is correct.

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 12(6x+12)? A. 6x+14 B. 12x+1 C. 3x+12 D. 3x+14 please answer

insens350 [35]

Step-by-step explanation:

B.12x + 1

if it helps brainiest lol

6 0

3 years ago

A circular garden has a circumference of 113 yards. Lars is digging a straight line along a diameter of the garden at a rate of

marin [14]

Answer:

Step-by-step explanation:

Circumference = $2\pi r = \pi d$ , where r is radius, and d is diameter

d=113/3.14=35.987, which is approximately 36

At 12 yards per hour, it will take 36/12=3 hours

5 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

2 years ago