Get into ax²+bx+c=0 form
subsitute u=x⁴
x⁸-3x⁴+2=0
(x⁴)²-3(x⁴)+2=0
u²-3u+2=0
factor
(u-2)(u-1)=0
set to zero
u-2=0
u=2
u-1=0
u=1
wait, u=x⁴
2=x⁴
1=x⁴
+/-1=x
the subsitution is u=x⁴
and the possible values for x are -1,
, and 1
Answer:
no false.
Step-by-step explanation:
Answer:
(-6,-4)
Step-by-step explanation:
The first endpoint of the line is (-6,8), we can call
x_1 = -6
and
y_1 = 8
Let the last endpoint have coordinates (x_2,y_2)
Also, the midpoint formula is:
(x_1+x_2)/2 , (y_1+y_2)/2
Now, plugging these values is the formula, we get:
(-6+x_2)/2 = -6
-6+x_2=-12
x_2=-12+6 = -6
x_2 = -6
Also
(8+y_2)/2=2
8+y_2=4
y_2=4-8=-4
y_2 = -4
The coordinates of the other endpoint is (-6,-4)
Step-by-step explanation:
hey.....
how are uh
Answer:
a-b=12
Step-by-step explanation:
(a²-b²)/(a+b) = 12
(a-b)(a+b)/(a+b)=12
a-b=12