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3 years ago

Determine the equation for the line that has a slope of -2 and a y intercept of 5

Mathematics

1 answer:

Reptile [31]3 years ago

8 0

Y = -2x + 5 remember Y = mx(slope) + b (y-int)

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A swimmer is racing to the other side of the

kiruha [24]

Either B or C. They look exactly the same but I can’t tell because the photo is blurry

y intercept is 75 and x intercept is 75/2.5=30

4 0

3 years ago

An experiment has four equally likely outcomes: E1, E2, Es, and E.Round your answers to three decimal places. a. What is the pro

V125BC [204]

Answer:

a. 0.25

b. 0.50

c. 0.75

Step-by-step explanation:

P(E1) = 0.25

P(E2) = 0.25

P(Es) = 0.25

P(E) = 0.25

a. Since there are 4 outcomes with the same probability of occurring, the probability of E occurring is:

$P(E) = \frac{1}{4}=0.25$

b. The probability of any two outcomes occurring is twice the probability of a single outcome occurring

$P(two\ outcomes) = 2*P(one\ outcome) = \frac{2}{4}=0.50$

c. The probability of any three outcomes occurring can be written as 100% minus the probability of the remaining outcome occurring

$P(three\ outcomes) = 1-P(one\ outcome) = 1-\frac{1}{4}=0.75$

6 0

4 years ago

55% of what number is 22?

Ilya [14]

Answer:
The number is 40

Explanation:
Assume that the number we are looking for is x.
We know that 55% of the number x is 22.
This means that:
55% of x = 22
55% * x = 22
0.55x = 22

Now, we will simply solve for x as follows:
0.55x = 22
x = $\frac{22}{0.55}$ 
x = 40

Hope this helps :)

5 0

3 years ago

Use parentheses to make the equation true: 9-8x2-1=3

Nana76 [90]

Try all ways to finish the answer example:
(9-8)*2-1=1
9-(8*2)-1=-8
9-8*(2-1)=1
all answers dont equal up to 3
and because there is no possible solution this is a troll question

5 0

4 years ago

The following table relates the weights and

MA_775_DIABLO [31]

The probability of randomly chosen tall and obese individuals is 0.30.

Firstly complete the given table and find the total of each row and column.

Tall Medium Short Total

Obese 18 28 14 60

Normal 20 51 28 99

Underweight 12 25 9 46

Total 50 104 51 205

We have to find P(Tall | Obese).

P(Tall | Obese) = P(Tall and Obese) / P(Obese)

Now, P(Tall and Obese) = 18 ÷ 205

And, P(Obese) = 60÷205

Substituting the above values,

P(Tall | Obese) = 18÷205/ 60÷205

P(Tall | Obese) = 18/60

P(Tall | Obese) = 0.30

Hence the probability of a tall and obese individual is 0.30.

To learn more about probability, visit: brainly.com/question/11234923

#SPJ9

8 0

1 year ago