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Answer:
(x, y) = (8, 2)
Step-by-step explanation:
The relevant equations are ...
3x -y = 22
x +2y = 12
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We can eliminate y by adding twice the first equation to the second.
2(3x -y) +(x +2y) = 2(22) +(12)
7x = 56
x = 8
Substituting into the first equation gives ...
3(8) -y = 22
y = 24 -22 = 2
The first number is 8; the second number is 2.
Divide both sides by eight
Answer:
d. (x+2)/(-x²-5)
Step-by-step explanation
ƒ(x) = x + 2/(2x²)
The function is undefined when x = 0.
b. ƒ(x) = (2x + 4)/(3x + 3)
The function is undefined when 3x + 3 = 0, i.e., when x = -1.
c. ƒ(x) = (6x - 5)/(x² - 7)
The function is undefined when x² - 7 = 0, i.e., when x = √7.
d. ƒ(x) = (x+2)/(-x²-5) = -(x+2)/(x² + 5)
The function would be undefined if x² + 5 = 0, i.e., if x² = -5. However, the square of a real number cannot be negative.
This function has no excluded values.
(1) will write us of the following form

(2) [do not it need explanation]

(3) Left place variable "y" and right place, variable "x" like this

(4) Integrate both members

(5) Solve us the integrals

(6) Isolate variable "y"

C: any cosntant