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stealth61 [152]
4 years ago
7

Bill and Joe leave their house at the same time heading in opposite directions. If Bill is driving three times faster than Joe a

nd it takes them three hours to be 120 miles apart, how fast is Bill driving?
Mathematics
1 answer:
Arisa [49]4 years ago
4 0

The problem statement gives you the relationship between their speeds, and it gives you information you can use to find their total speed. You solve this by finding the total speed, then the proportion of that belonging to Bill.

The total speed is (120 mi)/(3 h) = 40 mi/h.

The speed ratio is ...

... Bill : Joe = 3 : 1

so the speed ratio Bill : Total is ...

... 3 : (3+1) = 3:4.

Bill's speed is (3/4)×(40 mi/h) = 30 mi/h.

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2. (n/5)5 ≥ (11)5

n ≥ <u>55</u>

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Which person has the lowest ratio of blue to red marbles?
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Find x. A. 11√6/2 B. 22 C. 33 D. 11√3/2
Phoenix [80]

Answer:

B

Step-by-step explanation:

using the tangent ratio on the triangle on the right and the exact value

tan60° = \sqrt{3} , then letting the altitude be h

tan60° = \frac{opposite}{adjacent} = \frac{11\sqrt{6} }{h}  = \sqrt{3} ( multiply both sides by h )

11\sqrt{6} = h × \sqrt{3} ( divide both sides by \sqrt{3} )

11\sqrt{2} = h

using the sine ratio in the triangle on the left and the exact value

sin45° = \frac{\sqrt{2} }{2} , then

sin45° = \frac{opposite}{hypotenuse} = \frac{h}{x} = \frac{11\sqrt{2} }{x} = \frac{\sqrt{2} }{2} ( cross- multiply )

\sqrt{2} × x = 22\sqrt{2} ( divide both sides by \sqrt{2} )

x = 22

6 0
1 year ago
Add.<br><br> 3/2x+4 + 2x/3x+6<br><br> and it'd be great if you show you work, thank you! ♡
Vikki [24]

Answer:

<u>2 1/6x +10</u>

Step-by-step explanation:

All you need to do is combine like terms.

3/2x+<u>4</u>+2/3x+<u>6</u>

3/2x+<u>10</u>+2/3x

<u>3/2x + 2/3x</u>= <u>2 1/6x</u>

<u>2 1/6x+10</u>

7 0
4 years ago
An urn contains 6 red balls, 8 green balls, and 10 white balls. If balls are selected one by one (without replacing them after t
PIT_PIT [208]

Answer:

0.43478

Step-by-step explanation:

From the information given:

The \  required  \ probability = P(1st ball = red) \times P(2nd ball = red) + P(1st ball = red) \times P(2nd ball = white)  + P(2nd ball = red) \times P(1st ball = white) + P(1st ball = white) \times P(2nd ball = white)

= \dfrac{6}{6+8+10}\times  \dfrac{5}{5+8+10} +  \dfrac{6}{6+8+10} \times  \dfrac{10}{5+8+10} +  \dfrac{10}{6+8+10} \times  \dfrac{6}{5+8+10} \times  \dfrac{10}{6+8+10} \times  \dfrac{9}{5+8+9}

=(\dfrac{6}{24}\times \dfrac{5}{23})+ (\dfrac{6}{24}\times \dfrac{10}{23}) +( \dfrac{10}{24}\times \dfrac{6}{23} ) + (\dfrac{10}{24}\times \dfrac{9}{23})

= 0.05434782609 + 0.1086956522  + 0.1086956522  + 0.1630434783

= 0.4347826088

≅ 0.43478

8 0
3 years ago
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