Answer:
Step-by-step explanation:
If r varies directly with the square of m and inversely as s,
then 
where k is some constant
Given r = 12 when m = 6 and s = 4:
⇒ 
⇒ 
⇒ k = 
Therefore, substituting the found value of k into the original equation: 
Find r when m = 4 and s = 10:
⇒ 
⇒
Lim ln([(x+1)/x]^3x) as x ->.infinity =lim ln([(x+1)^(3x)]/[x^(3x)]) as s->infinity =lim ln((x+1)^(3x))-ln(x^(3x)) = infinity - infinity
your answer is e3 but you can use l'hopital if you liketake the log, get 3xln(1+1/x)which is in the form ∞×0 then use the usual trick of rewriting as ln(1+1/x)/1/3x
F(x) − g(x) = 2x^2 − 9x - (<span> -5x^2 + 4x)
</span>f(x) − g(x) = 2x^2 − 9x + 5x^2 - 4x
f(x) − g(x) = 7x^2 - 13x
They are 6;9;12;15;18 and 21
