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DerKrebs [107]
4 years ago
11

What title belongs in the circle labeled X in the diagram below?

Chemistry
1 answer:
PIT_PIT [208]4 years ago
3 0
Can you give a picture description? Or any answer choices?
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If you can smell your grandmother’s perfume from across the room, you are experiencing the result of which liquid property?
cestrela7 [59]
The appropriate answer is D. volatility. Volatility refers to the susceptibility of liquids to vaporize. Perfume is liquid when applied but because of volatility, it has a tendency to vaporize and so it will convert to a gas and diffuse across the room. The process by which a liquid changes to a vapor is called evaporation. 
5 0
3 years ago
Where does nearly all life get its energy from? *<br> Oxygen<br> A.Sun<br> B.Produce<br> C.Soil
meriva
The sun hope this helps
5 0
3 years ago
Read 2 more answers
Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas
Gwar [14]

The equation structure for the above mentioned reaction can be written as  

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

<u>Explanation:</u>

Considering the above reaction, When Boron sulfide, reacts with water more violently to form boric acid and hydrogen sulfide gas.

B_{2} S_{3}+H_{2} O \rightarrow H_{3} B O_{3}+H_{2} S \uparrow

In order to balance the equation, we can do as follows.There are 2 B - atoms on both sides of the equation, but only 2 H - atoms, and one O - atom on LHS, so we have to balance it by putting 6 in front of water and 2 in front of Boric acid and 3 in front of hydrogen sulphide gas, so that we have 2 B - atoms, 3 - S atoms, 12 H - atoms on both sides of the equation, and it is balanced. Balanced equation is given as,

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

Thus a Balanced equation of the above mentioned reaction is written.

8 0
3 years ago
Give two examples of solutions that you might find or prepare in a kitchen.
amm1812

Explanation:

solid liquid

solid gas

liquid solid

8 0
3 years ago
The normal freezing point of a certain liquid Xis-7.30°C but when l02. g of iron(III) chloride (FeCl3) are dissolved in 650. g o
IRISSAK [1]

Answer:

2.7 °C.kg/mol

Explanation:

Step 1: Calculate the freezing point depression (ΔT)

The normal freezing point of a certain liquid X is-7.30°C and the solution freezes at -9.9°C instead. The freezing point depression is:

ΔT = -7.30 °C - (-9.9 °C) = 2.6 °C

Step 2: Calculate the molality of the solution (b)

We will use the following expression.

b = mass of solute / molar mass of solute × kilograms of solvent

b = 102. g / (162.2 g/mol) × 0.650 kg = 0.967 mol/kg

Step 3: Calculate the molal freezing point depression constant Kf of X

Freezing point depression is a colligative property. It can be calculated using the following expression.

ΔT = Kf × b

Kf = ΔT / b

Kf = 2.6 °C / (0.967 mol/kg) = 2.7 °C.kg/mol

7 0
3 years ago
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