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Mkey [24]
3 years ago
10

WORTH 99 POINTS PLEASE ANSWER!!! The table shows the solubility of two substances in water at 20 °C. Solubility of Substances Ma

ss (kg) Solubility of Sodium Chloride (g per 100 g of water) Solubility of Lead Nitrate (g per 100 g of water) 100 L K 200 36 54 Part 1: What will be the values of L and K for 100 kg of each substance? Part 2: Explain your answer for Part 1.
Chemistry
2 answers:
DaniilM [7]3 years ago
8 0

Answer:

L is equal to 18 and K is equal to 27

If the solubility for L in 200kg of water is 36g then to find the solubility in 100kg of water, you would divided 36 by 2 to find half. You would do the same to find K, if in 200kg of water K's solubility is 54, you would divided 54 by 2 to get 27.

Explanation:

also you only set this question to 5 points not 99, if this helps at all could you mark me brainliest? :) have a great day!

Lunna [17]3 years ago
3 0

Answer:

the difference between k and l is that (k) is more soluble than (L) because the mass of 200 has lower grams than 100.

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Answer:

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Explanation:

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Unknown:

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Solution:

The combined gas law application to this problem can help us solve it. It is mathematically expressed as;

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

P, V and T are pressure, volume and temperature

where 1 and 2 are initial and final states.

Now,

 take the units to the appropriate ones;

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P₂ = 319kpa in atm gives 3.15atm

P₁  = 928kpa gives 9.16atm

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Input the values in the equation and solve for V₂;

        \frac{9.16  x 569}{402}   = \frac{3.15 x V_{2} }{305}

       V₂   = 1255.4L

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