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Mkey [24]
3 years ago
10

WORTH 99 POINTS PLEASE ANSWER!!! The table shows the solubility of two substances in water at 20 °C. Solubility of Substances Ma

ss (kg) Solubility of Sodium Chloride (g per 100 g of water) Solubility of Lead Nitrate (g per 100 g of water) 100 L K 200 36 54 Part 1: What will be the values of L and K for 100 kg of each substance? Part 2: Explain your answer for Part 1.
Chemistry
2 answers:
DaniilM [7]3 years ago
8 0

Answer:

L is equal to 18 and K is equal to 27

If the solubility for L in 200kg of water is 36g then to find the solubility in 100kg of water, you would divided 36 by 2 to find half. You would do the same to find K, if in 200kg of water K's solubility is 54, you would divided 54 by 2 to get 27.

Explanation:

also you only set this question to 5 points not 99, if this helps at all could you mark me brainliest? :) have a great day!

Lunna [17]3 years ago
3 0

Answer:

the difference between k and l is that (k) is more soluble than (L) because the mass of 200 has lower grams than 100.

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Explanation:

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An anion is formed when a valence election is gained by a non metal while a cation is formed when the metal ion misplaces a valence electron.

The effect of the anion of an ionic compound on the appearance of the solution is that the anion affects the color of the solution more than the intensity of the color.

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Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
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<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

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            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

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