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n200080 [17]
3 years ago
9

Why is second ionization energy larger than first ionization energy

Chemistry
2 answers:
polet [3.4K]3 years ago
8 0

Ionization energy is the energy required to remove an electron from a neutral atom. When an electron is removed from an atom, the neutral atom becomes positively charged. When another electron is attempted to be removed from the same atom,this requires more energy than the first one, as the attractive force between the electrons and protons are greater owing to the presence of the extra proton. In order to break this force we need more energy to remove the second electron. Hence the second ionization energy is greater than the first ionization energy.

rodikova [14]3 years ago
4 0

Hi!

Why is second ionization energy larger than first ionization energy?

The reason second ionization energy is larger is because it takes more energy to remove an electron from a poistively charged ion than it does from an neutral atom.

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Assertion (A): An orbital cannot have more than two electrons, moreover, if an orbital has two electrons they must have opposite
VMariaS [17]

Answer: Its option "A" Both A and R are true and R is the correct explanation of A.

Hope it helps

7 0
3 years ago
Read 2 more answers
A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi
Naddika [18.5K]
Imagine we have <span>mass of solvent 1kg (1000g)
According to that: </span>molality =n(solute) / m(solvent) =\ \textgreater \  4.8m = 4.8mole / 1kg
= 4.8 mole * 98 g/mole = 470g
m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \=\ \textgreater \  Molarity = 4.8 mole / 1.2 L = 4 M m(H2SO4)  which is =<span>470g

</span><span>m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =></span>
Molarity = n(solute) / V(solution) =\ \textgreater \
5 0
3 years ago
PLEASE HELP ME WILL DO ANYTHING ‼️‼️
deff fn [24]

Answer:

In first shell 2 electrons are present and 7 electrons are present in last shell

Explanation:

6 0
3 years ago
Calculate mass of hydrogen chloride produced from 11.3g H and 11.3g Cl. <br> H2 + Cl2 -&gt; 2HCl
S_A_V [24]

Answer:

22.6According to the law of conservation of mass, the total mass of reactants should be equal to the total mass of products. Here, total mass of reactants= 11.3+11.3=22.6

•

• • Mass of Hcl produced=22.6 g

4 0
3 years ago
Fluorine-21 has a half life of approximately 5 seconds. You have 340 grams, what fraction of the original nuclei would remain af
madreJ [45]
The half life equation is -->P(t) = Pi (0.5) ^ (t/c)
c is equal to the element to reach its half-life (5 seconds)t is equal to the duration of time the element is expose to (20 seconds)Pi is the initial amount (340)0.5 is the base of this exponential function to represent half-life.P(t) is the expression for the function of time

P(20) = 340 (0.5)^20/5P(20) = 340 (0.5) ^4P(20)= 21.25 grams
Fraction = P(t)/Pi              = P(20)/Pi              =21.25/340              =1/16
Therefore, when given 20 seconds, 340 grams of Fluorine-21 will degrade to 21.25 grams OR 1/16 of its original mass.
Hope this method helps! (This is my answer btw, I think you may have accidentally posted twice?)
7 0
3 years ago
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