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n200080 [17]
3 years ago
9

Why is second ionization energy larger than first ionization energy

Chemistry
2 answers:
polet [3.4K]3 years ago
8 0

Ionization energy is the energy required to remove an electron from a neutral atom. When an electron is removed from an atom, the neutral atom becomes positively charged. When another electron is attempted to be removed from the same atom,this requires more energy than the first one, as the attractive force between the electrons and protons are greater owing to the presence of the extra proton. In order to break this force we need more energy to remove the second electron. Hence the second ionization energy is greater than the first ionization energy.

rodikova [14]3 years ago
4 0

Hi!

Why is second ionization energy larger than first ionization energy?

The reason second ionization energy is larger is because it takes more energy to remove an electron from a poistively charged ion than it does from an neutral atom.

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What are the masses of the four different BrClBrCl molecules? Express the masses in atomic mass units using six significant figu
Sliva [168]

Answer ; The question is missing in some details, but here are he details ;

The two naturally occurring isotopes of bromine are

81Br (80.916 amu, 49.31%) and

79Br (78.918 amu, 50.69%).

The two naturally occurring isotopes of chlorine are

37Cl (36.966 amu, 24.23%) and

35Cl (34.969 amu, 75.77%).

Bromine and chlorine combine to form bromine monochloride, BrCl.

Explanation:

The detaile calculation is as shown in the attachment.

6 0
3 years ago
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

15,066.8 J=C\times 2.053^oC

C=7,338.92 J/^oC

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
3 years ago
When magnesium chloride reacts with water, 5.85 L HCl(g) is produced.
amid [387]

Answer: How many moles of HCl was produced?

⇒ 0.261 moles of HCl

How many moles of MgCl2 reacted?

⇒ 0.131 moles of MgCl2

What mass of MgCl2 reacted?

⇒ 12.4 g MgCl2

Explanation:

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3 0
3 years ago
Read 2 more answers
If 3.89 × 1024 atoms of a noble gas is collected and it has a mass of of 848 grams, this element is most likely a. He b. Ne c. A
bearhunter [10]

Answer:

Xenon

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Avogadro constant:-

N_a=6.023\times 10^{23}

Let the molar mass of the element is x g/mol

So,

6.023\times 10^{23} atoms have a mass of x g

Also,

3.89\times 10^{24} atoms have a mass of \frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24} g

This mass is equal to 848 g

So,

\frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24}=848

x= 131.3 g/mol

This mass correspond to xenon.

3 0
3 years ago
The removal of silver tarnish from silverware using aluminum foil and a solution of electrolyte is an example of
eimsori [14]

Answer:

The answer is C. An electrochemical cell.

Explanation:

The aluminum ion react with the sulfide to form aluminum sulfide.

8 0
3 years ago
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