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valentina_108 [34]
2 years ago
15

You have 20 shirts in your closet 4 blue 7 red 3 green and 6 black you pick one without looking what is the probability that you

pick a blue or black shirt
A) 1/4
B) 1/2
C) 3/50
Mathematics
1 answer:
bekas [8.4K]2 years ago
4 0
A.
Not 100% sure I haven’t done those problems in a while but good luck :)
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A(2/3x-3)=b solve for x
murzikaleks [220]

Answer:

x = \frac{3b}{2A} +\frac{9}{2}

Step-by-step explanation:

5 0
3 years ago
Which number should.be added to the data so that the range of the data is 31? 54,72,64,57
Sergio039 [100]

Answer:  41 or 85

<u>Step-by-step explanation:</u>

Range is the difference between the largest number and the smallest number.

The largest number is 72.  72 - 31 = 41

The smallest number is 54.  54 + 31 = 85

Adding either ONE of those numbers will result in a range of 31.

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3 years ago
162 water bottles and 96 equals what
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3 years ago
Without multiplying, tell whether the product 0.644 x 0.25 will be greater than 1 or less than 1? Explain how you know.
stepladder [879]

Answer:

Less than 1

Step-by-step explanation:

As 0.644 and 0.25 are less than 1, then

0.644=\frac{1}{p}

0.25=\frac{1}{q}

where p and q are greater than 1

then

0.644\times0.24=\frac{1}{p.q}

But p.q is greater than 1, so 1/(p.q) is smaller than 1

7 0
3 years ago
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Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
2 years ago
Read 2 more answers
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