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BartSMP [9]
3 years ago
12

A day at Camp there were 56 girls and 42 boys the campers need to be split into equal groups each has either all girls are all b

oys what is the greatest number of campers each can have
Mathematics
1 answer:
Olegator [25]3 years ago
3 0

number of girls = 56

number of boys = 42

highest common factor = 14

greatest number of campers per group is 14

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4 0
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QUIZ<br> Find the volume of the square pyramid.<br> 9 cm<br> 4 cm
kari74 [83]

Answer:

SEE BELOW

Step-by-step explanation:

V=a²h/3
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Divide using long division (4x^2-2x+7) divided by (x-1)
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Help please! Find the Surface area. Whoever gets it right ill give Brainliest!
11Alexandr11 [23.1K]

Answer:

284.6 square yards

284.6 yd^2

Step-by-step explanation:

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8 0
3 years ago
The equation y=123.1(1.065)* models the number of college students (in thousands) who studied abroad each year from 1998 through
xenn [34]

The estimate of the number of students studying abroad in 2003 is 169 and the estimate of the number of students studying abroad in 2018 is 433

<h3>a. Estimate the number of students studying abroad in 2003.</h3>

The function is given as:

y = 123(1.065)^x

Where x represents years from 1998 to 2013

2003 is 5 years from 1998.

This means that

x = 5

Substitute the known values in the above equation

y = 123(1.065)^5

Evaluate the exponent

y = 123 * 1.37008666342

Evaluate the product

y = 168.520659601

Approximate

y = 169

Hence, the estimate of the number of students studying abroad in 2003 is 169

<h3>b. Assuming this equation continues to be valid in the future, use this equation to predict the number of students studying abroad in 2018.</h3>

2018 is 20 years from 1998.

This means that

x = 20

Substitute the known values in the above equation

y = 123(1.065)^20

Evaluate the exponent

y = 123 * 3.52364506352

Evaluate the product

y = 433.408342813

Approximate

y = 433

Hence, the estimate of the number of students studying abroad in 2018 is 433

Read more about exponential functions at:

brainly.com/question/11464095

#SPJ1

4 0
1 year ago
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