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3 years ago

The answer to all of these problems

Mathematics

1 answer:

timurjin [86]3 years ago

4 0

Its easier to ask somebody face-to-face dude

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Which correctly describes how the graph of the inequality 5x + 2y = 13 is shaded?

exis [7]

Answer:

The answer is above the solid line.

Step-by-step explanation:

6 0

2 years ago

Simplify √49 + [√81 - x(9x = 14)]

eimsori [14]

$\longrightarrow{\green{- 9 {x}^{2} + 14x + 16}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$\sqrt{49} + [ \sqrt{81} - x \: (9x - 14) ] \\ \\ = \sqrt{7 \times 7} + [ \sqrt{9 \times 9} - 9 {x}^{2} + 14x] \\ \\ = \sqrt{( {7})^{2} } + [ \sqrt{ ({9})^{2} } - 9 {x}^{2} + 14x ] \\ \\ (∵ \sqrt{ ({x})^{2} } = x ) \\ \\ = 7 + (9 - 9 {x}^{2} + 14x) \\ \\ = 7 + 9 - 9 {x}^{2} + 14x \\ \\ = - 9 {x}^{2} + 14x + 16$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}$

3 0

3 years ago

F(x) = 3x + 6. Find the inverse of f(x).

Levart [38]

Answer:

$\tt C) \:\tt f^{-1}(x)=\cfrac{x-6}{3}$

Step-by-step explanation:

We're given,

$\tt f(x) = 3x + 6$

$\tt y=3x+6$

$\tt x=3y+6$

$\tt x-6=3y$

$\tt y=\cfrac{x-6}{3}$

$\tt f^{-1}(x)=\cfrac{x-6}{3}$

3 0

2 years ago

Solve the following proportion for the unknown variable: 15/d = 24/40

Pavel [41]

Answer:
d = 25

Explanation:
To get the value of d, we will need to isolate the d on one side of the equation.

This can be done as follows:
 $\frac{15}{d} = \frac{24}{40}$ 

First, we will do cross multiplication as follows:
40*15 = 24*d
600 = 24d

Then, we will isolate the d as follows:
24d = 600
 $\frac{24d}{24} = \frac{600}{24}$

d = 25

Hope this helps :)

4 0

3 years ago

Read 2 more answers

Question 6 of 10

Crank

Answer:

A, D

Step-by-step explanation:

When solving for x, we want to get all x terms on one side and all non-x terms on the other side. To make it so that x is by itself, we need to get rid of -3. We can do this by adding 3 to both sides, which demonstrates the addition property of equality. This property states that if you add a quantity to one side of an equation, you must add the same quantity to the other side as well.

3 0

3 years ago