Answer:
The inequality that you have is 
. You can use mathematical induction as follows:
Step-by-step explanation:
For 
we have:
Hence, we have that 
Now suppose that the inequality holds for 
and let's proof that the same holds for 
. In fact,
Where the last inequality holds by the induction hypothesis.Then,
Then, the inequality is True whenever 
.
Here u go the answer is 4/3
Just make 1 3/4 an improper fraction and multiply by 4:
1 3/4 = 7/4
7/4 * 4 = 7
Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.
7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)
Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.
Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.
This gives us our final answer:
(y+4)/(y+5)
