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stiks02 [169]
3 years ago
9

PLEASE HELP I WILL MARK BRAINLIST

Mathematics
1 answer:
shtirl [24]3 years ago
6 0
The minimum is 91. The first quartile is 112. The median is 173. The third quartile is 215. The maximum is 253.
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Divide 4 2/3 divided by 1 2/3
Natalka [10]
 4 2/3= 4 x 3 + 2 = 14/3
1 2/3 = 1 x 3 + 2 = 5/3
14/3 x (multiply) 3/5 (flip) = 14*3/5*3(cancel 3)=14/5.
14/5 14 divided by 5 = 2r4 = 2 4/5

=2 4/5
7 0
3 years ago
Write the fraction 1 8 as a percent round to the nearest hundredth of a percent where necessary
Airida [17]
.125 is the answer to that question

7 0
3 years ago
An item is priced at 60 dollars it is on sale for 40% off the regular price
pantera1 [17]
36, because 60 time .4 is 24 so 60 - 24 is 36 so it is 36 dollars.
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8 0
3 years ago
One more question on this test guys. please answer as fast as possible. If you do,
GaryK [48]

1. The given rectangular equation is x=2.

We substitute x=r\cos \theta.

r\cos \theta=2

Divide through by \cos \theta

r=\frac{2}{\cos \theta}

r=2}\sec \theta

\boxed{x=2\to r=2\sec \theta}

2. The given rectangular equation is:

x^2+y^2=36

This is the same as:

x^2+y^2=6^2

We use the relation r^2=x^2+y^2

This implies that:

r^2=6^2

\therefore r=6

\boxed{x^2+y^2=36\to r=6}

3. The given rectangular equation is:

x^2+y^2=2y

This is the same as:

We use the relation r^2=x^2+y^2 and y=r\sin \theta

This implies that:

r^2=2r\sin \theta

Divide through by r

r=2\sin \theta

\boxed{x^2+y^2=2y\to r=2\sin \theta}

4. We have x=\sqrt{3}y

We substitute y=r\sin \theta and x=r\cos \theta

r\cos \theta=r\sin \theta\sqrt{3}

This implies that;

\tan \theta=\frac{\sqrt{3}}{3}

\theta=\frac{\pi}{6}

\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}

5. We have x=y

We substitute y=r\sin \theta and x=r\cos \theta

r\cos \theta=r\sin \theta

This implies that;

\tan \theta=1

\theta=\frac{\pi}{4}

\boxed{x=y\to \theta=\frac{\pi}{4}}

6 0
3 years ago
-2.8 repeating as a fraction
Marizza181 [45]
0.8888888 = 8/9
2.8888888 = 26/9
-2.888888 = -26/9
3 0
3 years ago
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