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love history [14]

3 years ago

13

if the side length of the cube is 5 inches the volume of the cube is how many cubic inches and its total surface area is how man

y square inches

1 answer:

valina [46]3 years ago

5 0

Volume= 125cm cubed
Total Surface area=150 cm squared

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Find the area of the figure.

Aloiza [94]

Answer:

Step-by-step explanation:

4 0

2 years ago

Which of the following functions are homomorphisms?

Vikentia [17]

Part A:

Given $f:Z \rightarrow Z,$ defined by $f(x)=-x$

$f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y$

but

$f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy$

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.

Part B:

Given $f:Z_2 \rightarrow Z_2,$ defined by $f(x)=-x$

Note that in $Z_2$ , -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular $f(x)=x$

$f(x+y)=x+y \\ \\ f(x)+f(y)=x+y$

and

$f(xy)=xy \\ \\ f(x)\cdot f(y)=xy$

Therefore, the function is a homomorphism.

Part C:

Given $g:Q\rightarrow Q$ , defined by $g(x)= \frac{1}{x^2+1}$

$g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}$

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.

Part D:

Given $h:R\rightarrow M(R)$ , defined by $h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)$

$h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)$

but

$h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)$

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.

Part E:

Given $f:Z_{12}\rightarrow Z_4$ , defined by $\left([x_{12}]\right)=[x_4]$ , where $[u_n]$ denotes the lass of the integer $u$ in $Z_n$ .

Then, for any $[a_{12}],[b_{12}]\in Z_{12}$ , we have

$f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)$

and

$f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)$

Therefore, the function is a homomorphism.

7 0

3 years ago

Pls help answer question in picture

spayn [35]

Step-by-step explanation:

2 1/3

=2*3+1/3

=7/3

7 0

2 years ago

Simplify the expression<br> (5k^2)^3<br><br> 5k^6<br> 5k^8<br> 125k^5<br> 125k^6

o-na [289]

(5k²)³
(5³)(k²)³
125k⁶

The answer is D.

6 0

3 years ago

Please help if you can thanks ^^

Neko [114]

Given:

AD is an angle bisector in triangle ABC. $m\angle CAB=44^\circ, m\angle ACB=72^\circ, m\angle ABC=64^\circ$ .

To find:

The value of $m\angle ADC$ .

Solution:

AD is an angle bisector in triangle ABC.

$m\angle CAD=m\angle BAD=\dfrac{m\angle CAB}{2}$

$m\angle CAD=m\angle BAD=\dfrac{44^\circ}{2}$

$m\angle CAD=m\angle BAD=22^\circ$

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

Using angle sum property in triangle CAD, we get

$m\angle CAD+m\angle ADC+m\angle ACB=180^\circ$

$22^\circ+m\angle ADC+72^\circ=180^\circ$

$m\angle ADC+94^\circ=180^\circ$

$m\angle ADC=180^\circ-94^\circ$

$m\angle ADC=86^\circ$

Therefore, the angle of angle ADC is $86^\circ$ .

3 0

3 years ago