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dmitriy555 [2]
3 years ago
10

Help!? i dont understand. First question on top, and second question in bottom

Mathematics
1 answer:
mario62 [17]3 years ago
5 0
We know that:

$\sqrt[a]{x^b}=x^{\frac{b}{a}}

so:

1)

$(\sqrt[3]{t^4})\cdot(t^{\frac{-1}{2}})=(t^{\frac{4}{3}})\cdot(t^{\frac{-1}{2}})=
t^{\frac{4}{3}+\frac{-1}{2}}=t^{\frac{8}{6}+\frac{-3}{6}}=t^{\frac{8-3}{6}}=\boxed{t^{\frac{5}{6}}=\sqrt[6]{t^5}}

2)

x^{-\frac{2}{5}}=\dfrac{1}{x^{\frac{2}{5}}}=\boxed{\dfrac{1}{\sqrt[5]{x^2}}}

Answer 4)
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Find the value of x in (4x -5) = 7(x -5)​
Vlad1618 [11]

Answer: x = 10

Step-by-step explanation:

( 4 x − 5 ) = 7 ( x − 5 )

Simplify  7 ( x − 5 ) .

4 x − 5 = 7 x − 35

Move all terms containing  x  to the left side of the equation.

− 3 x − 5 = − 35

Move all terms not containing  x  to the right side of the equation.  

− 3 x = − 30

Divide each term by   − 3  and simplify.

x = 10

6 0
3 years ago
According to the scores on the last math test, 80%, or 20. of the students in the class received an A Find the number of student
Kitty [74]

Answer:

25 students

Step-by-step explanation:

.8x = 20

 x = 25 students

4 0
3 years ago
Consider the following data set: {4, 5, 6, 7, 10}. If you remove one of the numbers from the list, then the mean increases and t
Sauron [17]

Answer:

6

Step-by-step explanation:

Right now, the mean is 6.4 and the median is 6. If you take away 6, the mean would be 6.5 and the median will stay the same. The median will stay the same because when there is no middle number, you add the two closest numbers and divide by two.  

Hope it helped:)

5 0
3 years ago
A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m
arsen [322]

Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let <em>X</em> = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.

The sample of employed individuals selected is of size, <em>n</em> = 225.

An individual holding multiple jobs is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.

Conditions of Normal approximation to Binomial are:

  • np ≥ 10
  • n (1 - p) ≥ 10

Check the conditions as follows:

np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10

The distribution of the proportion of individuals who hold multiple jobs is,

p\sim N(p, \frac{p(1-p)}{n})

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

P(p

*Use a <em>z</em>-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

7 0
3 years ago
The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 7 to 5 . If there were
Nitella [24]

Answer: 6456

Step-by-step explanation:

Ratio of yes to no= 7:5

Number if yes= 3766

Since total number of yes is 3766. To find the total number of votes, 3766 / (7/7+5)

= 3766/ (7/12)

= 3766 × 12/7

= 45192/7

= 6456

There were 6456 total votes

5 0
3 years ago
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