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yKpoI14uk [10]
3 years ago
13

Can i still download an update for an xbox one game if it's not turned on

Computers and Technology
1 answer:
Aneli [31]3 years ago
3 0
<span>Yeah, they do. I think as long as the power brick glows white the system is in standby and will download anything in your queue.</span>
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Which of the following locations is the option to show hidden files or folders location
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Start menu "this pc" or "my computer"
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The first project that this position will work on is an embedded sensor that will send readings periodically to the cloud, and h
Mice21 [21]

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we need PLC(Programmable Logic Units) attached to the sensors  and those sensors will take the signals/values  and transfer them to the cloud .In cloud we store that information and send that information to the web application where user is able to view

Explanation:

it looks like a SCADA system. we can integrate PLC with SCADA

or

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3 years ago
In most programming languages, the compiler carries a preprocessing step to determine if certain statements will compile. For in
MakcuM [25]

Answer:

See explaination for program code

Explanation:

package com.company;

import java.io.IOException;

import java.nio.file.Files;

import java.nio.file.Paths;

import java.util.Stack;

/*

* A program which reads input from given text filename and prints

* whether it passed the pre-processing stage or not

* Sample input

* int A = (a + b);static void display(int x)

* {

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* }

* */

public class MyPreprocessor {

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* */

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String content = "";

try {

content = new String(Files.readAllBytes(Paths.get(filename)));

} catch (IOException e) {

e.printStackTrace();

}

return content;

}

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* Filters input since we are only concerned with

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*/

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case '[':

case ']':

case '{':

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case '(':

case ')':

case '*':

case '/':

output += text.charAt(i);

}

}

return output;

}

/*

* Uses stack to determine if input is valid or not

* */

public boolean parse(String input) {

Stack<Character> St = new Stack<Character>();

// '$' is special symbol to represent bottom of stack

St.push('$');

for(int i = 0;i<input.length();++i) {

Character symbol = input.charAt(i);

if(St.peek().equals(getOpenSymbol(symbol)))

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private static Character getOpenSymbol(Character symbol) {

switch (symbol) {

case '}': return '{';

case ']': return '[';

case ')': return '(';

case '*': return '*';

case '/': return '/';

default: return ' ';

}

}

public static void main(String[] args) {

MyPreprocessor preprocessor = new MyPreprocessor();

String inputText = preprocessor.readInput("src/input.txt");

String filteredInput = preprocessor.filterText(inputText);

if(preprocessor.parse(filteredInput))

System.out.println("preprocessing passed.");

else System.out.println("preprocessing failed!");

}

}

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True or false? If you’re posting the same content across different channels, make sure you post them simultaneously—on the same
alukav5142 [94]

Answer:

The answer is true.

Explanation:

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