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tester [92]
3 years ago
6

What is considered appropriate dress for men and women in the workplace? Select all that apply.

Computers and Technology
2 answers:
Andrew [12]3 years ago
8 0

Answer:

I guess clean, pressured pants or skirt

and

dress shirts and ties

Firdavs [7]3 years ago
5 0

Answer:

the first and last

Explanation:

because you don't want to reveal any things that are inappropriate but you still want to be comfortarible.

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How do you put a voice password on your computer using windows 10
valkas [14]
I think you need some time of camra voice recorder sorry if im wrong also sorry cuz i forgot what it is called
7 0
3 years ago
What is the definition of legal intrusion
AleksAgata [21]
My answer -

intrusion of rights, right of privacy, trespass

P.S

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5 0
3 years ago
Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Lynna [10]

Answer:

def print_popcorn_time(bag_ounces):

 if bag_ounces<3:

   print("Too Small")

 elif bag_ounces>10:

   print("Too Large")

 else:

   bag_ounces = bag_ounces*6

   print("%s Seconds\n" % bag_ounces)    

Explanation:

  • Using Python Programming Language
  • The function is defined to accept an int parameter
  • Within the function body, if...elif and else statements are used to print the desired output
  • note the use of the %s placeholder (formated output) and \n for a new line in the final print statement
4 0
3 years ago
Use the variables k, d, and s so that they can read three different values from standard input--an integer, a double, and a stri
Nat2105 [25]

Answer:

The c++ program to implement the given scenario is shown below.

#include <iostream>

using namespace std;

int main() {

   // variables declared as mentioned

   int k;

   double d;

   string s;

   cout << " Enter an integer value, a double value, a string value in the mentioned order " << endl;

   cin >> k >> d >> s;

   // variables printed in reverse order

   cout << " Reverse order " << endl;

   cout << s << " " << d << " " << k << endl;

   // variables printed in original order

   cout << " Original order " << endl;

   cout << k << " " << d << " " << s << endl;

   return 0;

}

OUTPUT

Enter an integer value, a double value, a string value in the mentioned order  

12 45.67 brainly

Reverse order  

brainly 45.67 12

Original order  

12 45.67 brainly

Explanation:

1. All the variables are declared as mentioned in the question.

int k;

   double d;

   string s;

2. The user is prompted to enter values for integer, double and string variables respectively. The input is accepted in the order mentioned above.

cin >> k >> d >> s;

3. The input is accepted in a single line since this is mentioned in the scenario that variables should be printed in the order in which they are read.

4. These variables are displayed to the standard output in reverse order – string, double, integer. The variables are displayed with exactly one space in between them.

cout << s << " " << d << " " << k << endl;

5. Then, variables are displayed in the original order – integer, double, string. The variables are displayed with exactly one space in between them.

cout << k << " " << d << " " << s << endl;

7 0
3 years ago
12.2 Sort an array in ascending order Write a program that gets a list of integers from input, and outputs the integers in ascen
notsponge [240]

Answer:

Explanation:

The following code is written in Java, it asks the user for the number of inputs that will be made and then the inputs. These inputs are placed into an array. Then the array is sorted and printed out to the terminal.

public static void sortArrayList() {

           ArrayList<Integer> sortedList = new ArrayList();

           Scanner input = new Scanner(System.in);

           System.out.println("Enter number of digits in Array");

           int numberOfInputs = input.nextInt();

           for (int i = 0; i < numberOfInputs; i++) {

                   System.out.println("Enter a number");

                   sortedList.add(input.nextInt());

           }

           int n = sortedList.size();

           for (int i = 0; i < n; i++)

               for (int j = 0; j < n-i-1; j++)

                   if (sortedList.get(j) > sortedList.get(j + 1))

                   {

                       // swap arr[j+1] and arr[j]

                       int temp = sortedList.get(j);

                       sortedList.set(j, sortedList.get(j + 1));

                       sortedList.set(j + 1, temp);

                   }

           for (int x : sortedList) {

               System.out.println(x);

           }

       }

7 0
3 years ago
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