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elena-14-01-66 [18.8K]
3 years ago
15

In rhombus EFGH below, EF= 13m and DG = 5m, Find the area of the rhombus.

Mathematics
1 answer:
Mariana [72]3 years ago
6 0

Answer:

the correct answer is 120 square meters

Step-by-step explanation:

DG is a half diagonal and it intersects with the other diagonal at 90°. So it forms a right angle triangle. Using Pythagoras theorem

13^2-5^2=d^2

169-25=d^2

144=d^2

d=√144

d=12

so the other half diagonal is 12m

the two diagonals will be 2×5 and 2×12

the two diagonals will be 10m and 24m

area of a rhombus=1/2d1d2

area of the rhombus= 1/2×10×24

area of the rhombus=120 square meters

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Dmitry_Shevchenko [17]

Answer:

12412

Step-by-step explanation:

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3 years ago
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The Quadratic Equation c² + 6c+ 8 = 0<br><br> Show work please
Bad White [126]
The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
c = (-6(+/-)√(6²-4(1)(8))/2(1)
4.) Simplify
c = (-6(+/-)√(36-(4*8))/2
c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
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*Simplify again:
c = -4/2 AND c = -8/2
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The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)
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3 years ago
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The area of a trapezoid is 39 square millimeters. The height of the trapezoid is 6 millimeters. One of the base legths of the tr
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-------------------------

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On a coordinates plane, a line passes through ( - 2 , 3 ) and ( 2 , 6 ). Which of the followings lies on the same line.
Dahasolnce [82]

By direct comparison and definition of <em>line</em> segment  we notice that the point (x, y) = (- 6, 0) lies on the <em>line</em> segment <u>AB</u> as each <u>AP</u> is a multiple of former. (Correct choice: C)

<h3>What point lies on a line segment?</h3>

According to linear algebra, a point lies in a <em>line</em> segment if its vector is a multiple of the vector that generates the <em>line</em> segment itself, that is:

<u>AB</u> = k · <u>AP</u>        (1)

The vector that generates the <em>line</em> segment is:

<u>AB</u> = (2, 6) - (- 2, 3)

<u>AB</u> = (4, 3)

And the vectors related to each point are:

Case A

<u>AP</u> = (- 2, 12) - (- 2, 3)

<u>AP</u> = (0, 9)

Case B

<u>AP</u> = (6, 12) - (- 2, 3)

<u>AP</u> = (8, 9)

Case C

<u>AP</u> = (- 6, 0) - (- 2, 3)

<u>AP</u> = (- 4, - 3)

Case D

<u>AP</u> = (- 6, 6) - (- 2, 3)

<u>AP</u> = (- 4, 3)

By direct comparison and definition of <em>line</em> segment  we notice that the point (x, y) = (- 6, 0) lies on the <em>line</em> segment <u>AB</u> as each <u>AP</u> is a multiple of former. (Correct choice: C)

To learn more more on line segments: brainly.com/question/25727583

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4 0
1 year ago
ANSWER FOR 20POINTS PLEASE
krok68 [10]

Answer:

| {7}^{2}  - 8|  =  |49 - 8 =  |41|  = 41

7 0
3 years ago
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