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alexandr1967 [171]
2 years ago
12

“Draw the graph of the line with equation y=3/4x-2”

Mathematics
1 answer:
Ugo [173]2 years ago
3 0

Step-by-step explanation:

You have multiple ways, all revolving around finding 2 points.

The easiest point to use is the y intercept (the value of y when x=0), and is the constant term, giving you (0; -2)

The second point can be found in a number of ways:

  • Look for the x intercept (when y=0), and you will get some point by solving for x;
  • put any value of x you haven't used so far (ie, 0), compute it, and you will find a second point.
  • plug a "smarter" value of x that will make computation easy: in this case you have a fraction, so I would pick the denominator to simplify: (you got \frac34, so x=4 \rightarrow y=\frac34(4)-2 = 3-2=1 giving a second point (4;1))
  • since the equation is in <em>slope-intercept </em>form, Just remember the slope tells you how many vertical units you move (numerator) when you move right the number of units in the denominator, with the sign telling you up or down: in our case you move 3 up (since it's positive) every 4 "steps" right.

In any case, the graph will look something like the one in the image

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The model represents an equation. What value of x makes the equation true?
Cerrena [4.2K]

Answer:

C

Step-by-step explanation:

(-3) x 4 = (-12) + 6 = -6

3 + 3 = 6 + (-12) = -6

(-6) = (-6)

Because adding positive to negative is like subtracting the negative if that makes sense.

Hope this helps!

Have a great day!

Plz mark brainliest

6 0
3 years ago
Read 2 more answers
Write the perimeter of the triangle as a simplified expression
ioda

Answer: 10y + 1

Step-by-step explanation:

The perimeter is the total distance round the figure.

Now, in this case it is going to be

Perimeter = 3y + 5 + 6y + y - 4

= 3y + 6y + y + 5 - 4

= 10y + 1

3 0
3 years ago
Principal is __________.
bearhunter [10]

Answer:

B. the initial amount of money invested

Step-by-step explanation:

Principal is the money invested or the money that a lender lend the borrower. Such money is the basis on which the interest payable will be calculated after considering the numbers of years and installments.

4 0
3 years ago
In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: AC, if CD = 6√2 in.
klio [65]

Answer:

AC = 12 units.

Step-by-step explanation:

Δ ACD is right-angled. ( as CD ⊥ AB).

cos 45° = CD / AC = 6√2 / AC

AC = 6√2 / cos 45°

AC = 6√2 / 1 /√2

= 6√2 *√2

= 6 * 2

= 12   (answer)

HOPE THIS HELPED ;3

5 0
3 years ago
A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na
ira [324]

Answer:

Approximately 58.2\; \text{nautical miles} (assuming that the bearing is {\rm S$29^{\circ}$W}.)

Step-by-step explanation:

Let v denote the speed of the ship, and let t denote the duration of the trip. The magnitude of the displacement of this ship would be v\, t.

Refer to the diagram attached. The direction {\rm S$29^{\circ}$W} means 29^{\circ} west of south. Thus, start with the south direction and turn towards west (clockwise) by 29^{\circ} to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of v\, t. The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly 29^{\circ}.

Since the hypotenuse is of length v\, t, the dashed line segment opposite to the \theta = 29^{\circ} vertex would have a length of:

\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}.

Substitute in \begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned} and t = 6\; \text{hour}:

\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}.

7 0
2 years ago
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