Answer:
Hence the carnival game gives you better chance of winning.
Step-by-step explanation:
Let the event of win be given by 1/10 in the game of rifle then the event of loose is given by 9/10
the
Odds in favor of a game are given by = P(Event)/ 1- P(Event)
Odds in favor of winning a rifle are given by = 1/10/ 1- 1/10
=1/10/9/10
=1/9
= 0.111
The probability of winning aa rifle game is 0.111
The probability of winning the carnival game is 0.15
Comparing the two probabilities 0.111:0.15
The probability of winning carnival game is greater than winning a rifle game
0.15>0.11
Hence the carnival game gives you better chance of winning.
Hello :) we got similar answers but i believe you made a few distributing mistakes! hopefully my work makes sense, if not i’ll totally try to explain more
p.s i might be too late whoops
p.p.s i’m in a higher grade but i haven’t done this kinda math in a longgg time haha so if you think i did something wrong trust your gut ✌️
Answer:
Great work!
Step-by-step explanation:
These kind of questions are calculated through Riemann Sum. You can evaluate any definite integral using the Riemann Sum. It should be in the following form:
f(x)dx on the interval [a, b], or

Now f(x) is simply y. Therefore in this example y = x^3 - 6x. We just need the sufficient amount of data to apply the Riemann Sum, including the interval [a, b] that bounds the area, and the the number of rectangles 'n' that we need to use.
Consider an easier approach to this question: (First attachment)
Graph: (Second Attachment)
my brother did that too but I'm sorry i cant help you but I'm gonna say just keep up the good work
Answer:
63 i think
Step-by-step explanation: