For a right triangle with legs legnth a and b and hyptonuse c
a^2+b^2=c^2
9 feet from base, that's one leg
wire is hypotnuse, it's 1 more than height on tree
c=b+1
so
9^2+b^2=(b+1)^2
81+b^2=b^2+2b+1
minus b^2+1 from both sides
80=2b
divide both sides by 2
40=b
c=b+1
c=40+1
c=41
legnth of wire is 41ft
Answer:
x - -5.78526086, -1.50769051, 2.29295138
Step-by-step explanation:
graph each side of the equation. the solution si the x-value of the point of intersection.
Answer:
The answer to your question is 32 rose and 8 tulip
Step-by-step explanation:
Data
rose/ 4 = tulip
total number of arrangements = 40
Rose arrangement = R = ?
Tulip arrangement = T = ?
Process
1.- Write equations to solve this problem
R/4 = T
R + T = 40
2.- Solve the system by substitution
R + R/4 = 40
(4R + R) / 4 = 40
4R + R = 4(40)
5R = 160
R = 160 / 5
R = 32
- Find T
32 + T = 40
T = 40 - 32
T = 8
3.- Conclusion
She made 32 rose arrangement and 8 tulip arrangements.
Answer:
sixty-two plus 7 times a number h
Step-by-step explanation:
