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Nat2105 [25]
3 years ago
5

Question Solve the equation using the Properties of Equality. 14y +41 = 97

Mathematics
1 answer:
Mariana [72]3 years ago
4 0

Answer:

4

Step-by-step explanation:

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A parallelogram has vertices A(-2,1), B(3,2), C(4,6), D(-1,5). At what point do the diagonals intersect? PLZZ HELPPPP
Ymorist [56]

Answer:

I believe the A goes with the B the B goes with D that al I know soryy

3 0
3 years ago
Simply (cotθ-cscθ)^2
DIA [1.3K]

Answer:

[(cosθ-1)^2]/(sinθ)^2

Step-by-step explanation:

(cotθ-cscθ)^2

(cotθ)^2-<em>2cscθcotθ</em>+<u>(cscθ)^2</u>

(cosθ/sinθ)^2-2<em>(cosθ/(sinθ)^2) +</em><u>1/(sinθ)^2</u>

All have same denominator, (sinθ)2, add/subtract

((cosθ)^2-2cosθ+1)/(sinθ)^2

Factor the top

[(cosθ-1)^2]/(sinθ)^2

7 0
3 years ago
Michelle is scuba diving. Her position changes from -2.1m to -38.6m in 6 1/4 min. What is the average change in Michelle's posit
tankabanditka [31]

Answer: 5.824 m / min

Step-by-step explanation:

Change in position = -2.1m to -38.6m

Distance = |-38.6 m - (-2.1m) |

=|-36.5| m

= 36.5 m

Time = 6\dfrac14\ min=\dfrac{6\times4+1}{4}\ min

=\dfrac{25}{4}\ min

The average change in Michelle's position each minute = \dfrac{36.5}{\dfrac{25}{4}}\text{ m/min}

=\dfrac{36.4\times4}{25}\text{ m/min}\\\\= 5.824\text{ m/min}

Hence, the average change in Michelle's position each minute = 5.824 m / min

3 0
3 years ago
A mass oscillating up and down on the bottom of a spring (assuming perfect elasticity and no friction or air resistance) can be
alexdok [17]

The motion of the mass as it moves on the bottom of the spring is a

repetitive motion.

  • \mathrm{The \ motion \ of \ the \ mass \ attached \ to \ the \ spring \ is \ }\displaystyle d = 6 \cdot sin\left(\frac{\pi}{2} \cdot t \right)

Reasons:

The general form of the equation of the simple harmonic motion of the

mass is <em>d</em> = a·sin(ω·t)

Where;

d = The distance of the mass from the rest position

a = The maximum displacement of the mass from the equilibrium position = 6 cm

ω = The frequency of rotation

t = The time of motion

ω = The frequency of rotation

\displaystyle \omega = \mathbf{\frac{2 \cdot \pi}{T}}

Where;

T = The time to complete one cycle (the period of oscillation) = 4 seconds

\displaystyle \omega = \frac{2 \cdot \pi}{4} = \frac{\pi}{2}

Combining the above values gives the modelling equation as follows;

\displaystyle d = 6 \cdot sin\left(\frac{\pi}{2} \cdot t \right)

Learn more here:

brainly.com/question/12904891

3 0
2 years ago
2+(5+y) I need help pls! If you know the answer to this problem, please explain, THANK YOU!!!
anzhelika [568]

Answer:

y= -7

Step-by-step explanation:

I'm not sure if this is what you are looking for but here you go!

If the equation is set equal to zero.

2+(5+y)=0          This is the original expression, we need to find the value for y.

5+y= -2              We move the two to the right to remove it from the left side of                    

                          the equation.

y= -7                   We repeat the same thing as we did in the last step, except              

                          with the value 5. This then gives us our y-value, which is -7.

I hope this helps!

7 0
4 years ago
Read 2 more answers
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