<span>The expression that shows the result of applying the distributive property to 3(1/5x − 1/7) is:
3/5(x) - 3/7
I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions here in Brainly.
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❖ The length of the field is 91 m.
Divide to find the missing length:
4641 ÷ 51 = 91
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Jewelery maker has
24 jade beads
30 teak Beads
She has to make necklaces with each necklace having the same number of beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are as follows
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
Answer:
Option 4 is correct. The length of PR is 6.4 units.
Step-by-step explanation:
From the given figure it is noticed that the triangle PQR and triangle MQR.
Let the length of PR be x.
Pythagoras formula
![hypotenuse^2=base^2+perpendicular^2](https://tex.z-dn.net/?f=hypotenuse%5E2%3Dbase%5E2%2Bperpendicular%5E2)
Use pythagoras formula for triangle PQM.
![PM^2=QM^2+PQ^2](https://tex.z-dn.net/?f=PM%5E2%3DQM%5E2%2BPQ%5E2)
![PM^2=(6)^2+(8)^2](https://tex.z-dn.net/?f=PM%5E2%3D%286%29%5E2%2B%288%29%5E2)
![PM^2=36+64](https://tex.z-dn.net/?f=PM%5E2%3D36%2B64)
![PM^2=100](https://tex.z-dn.net/?f=PM%5E2%3D100)
![PM=10](https://tex.z-dn.net/?f=PM%3D10)
The value of PM is 10. The length of PR is x, so the length of MR is (10-x).
Use pythagoras formula for triangle PQR.
![PQ^2=QR^2+PR^2](https://tex.z-dn.net/?f=PQ%5E2%3DQR%5E2%2BPR%5E2)
![(8)^2=QR^2+x^2](https://tex.z-dn.net/?f=%288%29%5E2%3DQR%5E2%2Bx%5E2)
.....(1)
Use pythagoras formula for triangle MQR.
![MQ^2=QR^2+MR^2](https://tex.z-dn.net/?f=MQ%5E2%3DQR%5E2%2BMR%5E2)
![(6)^2=QR^2+(10-x)^2](https://tex.z-dn.net/?f=%286%29%5E2%3DQR%5E2%2B%2810-x%29%5E2)
![36=QR^2+x^2-20x+100](https://tex.z-dn.net/?f=36%3DQR%5E2%2Bx%5E2-20x%2B100)
.... (2)
From equation (1) and (2) we get
![36-x^2+20x-100=64-x^2](https://tex.z-dn.net/?f=36-x%5E2%2B20x-100%3D64-x%5E2)
![20x-64=64](https://tex.z-dn.net/?f=20x-64%3D64)
![20x=128](https://tex.z-dn.net/?f=20x%3D128)
![x=6.4](https://tex.z-dn.net/?f=x%3D6.4)
Therefore length of PR is 6.4 units and option 4 is correct.
Answer:
2x=0 x-3=0
Step-by-step explanation:
2x^ 2 - 6x = 0,
Factor out 2x
2x(x-3) =0
Using the zero product property
2x=0 x-3=0
x=0 x=3