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AlladinOne [14]

3 years ago

13

Graph f(x)=8x^2+16x+3

1 answer:

Hoochie [10]3 years ago

3 0

Answer:

use desmos to graph it

Step-by-step explanation:

heres a picture

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How to work it out and get it right

shtirl [24]

OOH, that's tricky--- give a shot first though!

5 0

3 years ago

What is number 3??????????????????

notsponge [240]

If its the one under the one with a written answer(the first on blank at the top) its b. 20% did not arrive.

6 0

3 years ago

Read 2 more answers

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago

2. Solve the system of equations by elimination 8x + 14y = 4 -6x -7y = 10

diamong [38]

Answer:

This is the answer of your question.

3 0

3 years ago

a line has a slope of -2/3 for a pair of points on the line. Find the missing coordinate if the points are (-1,y) and (4,7)

masha68 [24]

Answer:

The missing co-ordinate is: (-1, $\frac{31}{3}$ ).

Step-by-step explanation:

Given the slope of a line and a point on it, we determine the equation of the line by slope - one point form.

Slope - one point form: (y - y₁) = m(x - x₁)

Where, (x₁,y₁) is the point passing through the line.

Here the slope is $\frac{-2}{3}$ and the point (x₁,y₁) = (4,7).

Therefore the equation would be:

y - 7 = $\frac{-2}{3}$ (x - 4)

⇒ 3y - 21 = -2x + 8

⇒ 2x + 3y - 29 = 0 is the equation of the line.

Now it is given that (-1,y) also passes through the line, this point should satisfy the equation.

⇒ 2(-1) +3y = 29

⇒ 3y = 31 i.e., y = $\frac{31}{3}$

Therefore, the missing co-ordinate is: (-1, $\frac{31}{3}$ ).

8 0

3 years ago