Answer:
|88-x| ≤ 14
Step-by-step explanation:
their score has to be within 14 points of 88.
if their score is above 88, the number will be negative, but the absolute value makes the number positive. if that number is still within 14 of 88, they pass.
if their score is below 88, the number will be negative, and the absolute value keeps the number positive. if that number is still within 14 of 88, they pass.
For #3, you just have to plug in the numbers for x.
It tells you what to substitute for x in the question. (x = 0, 1, 2, 3, 4, 5, and 6)
For example, let's substitute 0 for x.
6x - x² (the 2 means square the number, or multiply it by itself)
6(0) - (0)²
0 - 0
= 0.
You'll do that to all the numbers (1-6) and fill out the table.
For #4, you have to solve using the distributive property to find out if the equations on both sides are equal.
I'll do the first one for you.
6a - 8 = 2 (3a - 5)
6a - 8 = 6a - 10
They're not equal.
Answer:
132 students
Step-by-step explanation:
Mr Smith offers to take extra help session for students after school
The day after the help session 11 of his students were talking and found out that only 2 had stayed up for the help session
= 2/11
There were actually a total number of 24 students that stayed
We are asked to find the number of student that Mr Smith teaches throughout the day
Let x represent the number of students that were taught during the day
Therefore, the number of student that Mr Smith teaches during the day can be calculated as follows
2/11=24/x
Cross multiply both sides
2 × x = 24 × 11
2x= 264
Divide both sides by 2
2x/2=264/2
x= 132
Hence Mr Smith teaches 132 students during the day.
Answer:
Triangles ABE and CDE are congruent by AAS.
Step-by-step explanation:
AB ≅ DC (Opposite sides of a parallelogram are congruent.
m < AEB = m < DEC (Vertical angles).
m < ABE = m < EDC ( Alternate Interior angles).
So triangles ABE and CDE are congruent by AAS.
