quotient is 98 1/2
<u> 0098 </u> 14/28
28 | 2758
<u> 252 </u> * 9 x 28
238
<u> 224 </u> * 8 x 28
14
2758 ÷ 28 = 98 14/28 simplified to 98 1/2
Answer:
Check the explanation
Step-by-step explanation:
The odds are 4 to 1 against, so we can estimate the probability of success (p) as

The expected pay for every success is 3 to 1, so we lose $1 for every lose and we gain $3 for every win.
The number of winnings in the 100 rounds to be even can be calculated as:

We have to win at least 25 rounds to have a positive payoff.
As the number of rounds is big, we will approximate the binomial distribution to a normal distribution with parameters:

The z-value for x=25 is

The probability of z>1.25 is
P(X>25)=P(z>1.25)=0.10565
There is a 10.5% chance of having a positive payoff.
NOTE: if we do all the calculations for the binomial distribution, the chances of having a net payoff are 13.1%.
Answer:
I'm not sure but I think the answer may be owbfosbeosdhslse skdneomsdeialsbs sisnnsgs
Answer:
1> x => - 5 and 7> y => - 4
Step-by-step explanation:
X belongs to [-5,1) and y belongs to [-4,7)