Answer:
Expression: 0.15 * 20
Equation: 0.15 * 20 = 3
Step-by-step explanation:
This expression was found by dividing 15% by 100 to convert it into a decimal (0.15) that can be used to multiply with 20 to get your answer.
Answer:
21 child tickets
Step-by-step explanation:
For this problem, you'd use a system of equations.
First, define your variables.
x = # of child tickets sold
y = # of adult tickets sold
There were 4 times as many adult tickets (y) as child tickets (x) sold, so:
4 x = y
4 x - y = 0
93 (4 x - y = 0)
372 x - 93 y = 0
The total revenue was $909.30, adult tickets were $9.30 each, child tickets were $6.10 each, so:
6.10 x + 9.30 y = 909.30
10 (6.10 x + 9.30 y = 909.30)
61 x + 93 y = 9093
372 x - 93 y = 0
433 x = 9093
433 x / 433 = 9093 / 433
x = 21
Answer:
![y = .5x^2 -2x -5](https://tex.z-dn.net/?f=y%20%3D%20.5x%5E2%20-2x%20-5)
Step-by-step explanation:
Well we can start by seeing if the parabola is the same width by comparing it to its parent function ( y = x^2 )
In y = x^2 the 2nd lowest point is just up 1 and right 1 away from the vertex.
This is not true for our parabola.
So we can widen it by to the desidered width by making the x^2 into a .5x^2.
So far we’ve got y = .5x^2
Now the parabola y intercept is at -5.
So we can add a -5 into the equation making it.
y = .5x^2 - 5
Now for the x value.
So we can find the x value by seeing how far away the parabola is from from the y axis.
So the x value is -2x.
So the full equation is ![y = .5x^2 -2x -5](https://tex.z-dn.net/?f=y%20%3D%20.5x%5E2%20-2x%20-5)
Look at the image below to compare.
A circle with a radius of 7cm. I know this is late lol. A square is equilateral so all sides are equal. To find the side lengths given the area you just need to take the square root of the area. You get 14cm. If you put a circle in the square the radius would just be half of one side.