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Rufina [12.5K]
3 years ago
7

Solve: |4x + 5| + 8 >(or equal to)45

Mathematics
1 answer:
KatRina [158]3 years ago
8 0
This is pretty simple once you get used to this


First set it equal to the original and the negative one
(>_) is the bigger and equal to part

4x+5>_45 or 4x+5>_-45

Then solve for x for both


4x>_40. 4x>_-50
X>_10 X>_-25/2
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What is the remainder R when the polynomial p(x) is divided by (x + 1)? Is (x + 1) a factor of p(x)? p(x) = -3x4 + 2x3 - x2 + 6
vodka [1.7K]

Answer:

(x+1) is a factor with remainder 0.

Step-by-step explanation:

We divide (x+1) into the polynomial -3x^4+2x^3-x^2+6 through long division or synthetic. We choose long division and look for what will multiply with (x+1) to make the polynomial -3x^4+2x^3-x^2+6 .

(x+1)(-3x^3)=-3x^4-3x^3

We subtract this from the original -3x^4-(-3x^4)+2x^3-(-3x^3)-x^2+6.

This leaves 5x^3-x^2+6. We repeat the step above.

(x+1)(5x^2)=5x^3+5x^2.

We subtract this from 5x^3-(5x^3)-x^2-(5x^2)+6=-6x^2+6. We repeat the step above.

(x+1)(-6x)=-6x^2-6x.

We subtract this from -6x^2-(-6x^2)+0x-(-6x)+6=6x+6. We repeat the step above.

(x+1)(6)=-6x+1.

We subtract this from 6x-(6x)+6-(6)=0. There is no remainder. This means (x+1) is a factor.


7 0
3 years ago
What is the end behavior of this radical? f(x) = 4 square root x - 6
Tanzania [10]

Answer:

I think you can answer it with a chart, I guess, of course I'm not sure‍♀️

8 0
3 years ago
Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal distribution. A random sample
GuDViN [60]

Answer: (628.48,\ 661.52)

Step-by-step explanation:

Given : Sample size : n=16 , which is a small sample (, 30) so we use t-test.

Sample mean : \overline{x}=645 \text{ hours}

Standard deviation : \sigma = 31 \text{ hours}

Significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=2.131

The confidence interval for population mean is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=645\pm(2.131)\dfrac{31}{\sqrt{16}}\\\\\approx645\pm16.52\\\\=(645-16.52,\ 645+16.52)\\\\=(628.48,\ 661.52)

Hence, a 95% confidence interval for the population mean \mu = (628.48,\ 661.52)

6 0
3 years ago
An airline company claims in a recent advertisement that more than 94% of passenger luggage that is lost is recovered and reunit
Genrish500 [490]

Answer:

The null hypothesis is  H_o :  p  \le  0.94

The alternative hypothesis is   H_a :  p  >  0.94

Step-by-step explanation:

From the question we are told that

  The sample size is n =  315

   The population proportion is  p =  0.94

   The number of luggage that was recovered and reunited with the passenger in one day is  k =  276

   Generally the sample proportion is  mathematically represented as

       \r p = \frac{k}{n}

=>      \r p = \frac{276}{315}

=>      \r p = 0.876  

The null hypothesis is  H_o :  p  \le  0.94

The alternative hypothesis is   H_a :  p  >  0.94

8 0
3 years ago
The sum of Fred and Amanda's age is
sveta [45]

Answer:

so 3 x 109 =327+ 1 =328

Step-by-step explanation:

i think. so freds age is 3 times her age plus one so 328

6 0
3 years ago
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