I think it's a^2 b^2 + 6ab + 9
Answer:
Option A.
Step-by-step explanation:
In an experiment a mouse took the mean time to find its way through a maze = 18 seconds.
So the mean time μ = 18
So null hypothesis says,
H₀ : μ = 18
Then a researcher thought that the mice can complete the maze faster than the time taken earlier.
So he thinks mean time taken by 10 mice will be less than 18 seconds.
Or μ < 18
Alternate hypothesis says will be
Hₐ : μ < 18
Therefore, null hypothesis and alternate hypothesis will be
H₀ : μ = 18
Hₐ : μ < 18
Option A. will be the answer.
The independent variable (the one they want) is the # of hours worked, since that determines the price.
All the other answers contain information not included in the problem
The answer is B. y = -1/5x +1/2.
EXPLANATION
First solve for the slope:

After finding the slope, look for the linear equation with the same value of m (parallel equation).
Answer: 0.0035
Step-by-step explanation:
Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
i.e.
and
Let x denotes the readings on thermometers.
Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_
![P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035](https://tex.z-dn.net/?f=P%28X%3E2.7%29%3D1-P%28%5Cxleq2.7%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B2.7-0%7D%7B1%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq2.7%29%5C%20%5C%20%5B%5Cbecause%5C%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.9965%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%20%5C%5C%5C%5C%3D0.0035)
Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035
The required region is attached below .