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3 years ago

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Winnie is driving at a constant rate. It takes her 4 hours to drive from her home in Dallas to her parents’ house in Houston, Te

xas. If Winnie drives at 50 miles per hour, what is the greatest number in the range of this situation?

1 answer:

artcher [175]3 years ago

5 0

Answer:

200 mi

Step-by-step explanation:

distance = rate times time. In this situation, max. dist. = (50 mph)(4 hrs) = 200 mi.

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Find the product mentally. (ab + 3)2 ab2 + 6ab + 9 2ab + 6 a2b2 + 6ab + 9

Contact [7]

I think it's a^2 b^2 + 6ab + 9

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4 years ago

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Experiments on learning in animals sometimes measure how long it takes a mouse to find its way through a maze. The mean time is

Sladkaya [172]

Answer:

Option A.

Step-by-step explanation:

In an experiment a mouse took the mean time to find its way through a maze = 18 seconds.

So the mean time μ = 18

So null hypothesis says,

H₀ : μ = 18

Then a researcher thought that the mice can complete the maze faster than the time taken earlier.

So he thinks mean time taken by 10 mice will be less than 18 seconds.

Or μ < 18

Alternate hypothesis says will be

Hₐ : μ < 18

Therefore, null hypothesis and alternate hypothesis will be

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Hₐ : μ < 18

Option A. will be the answer.

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3 years ago

May I also have help with this question

KATRIN_1 [288]

The independent variable (the one they want) is the # of hours worked, since that determines the price.

All the other answers contain information not included in the problem

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4 years ago

Read 2 more answers

r-ruslan [8.4K]

The answer is B. y = -1/5x +1/2.

EXPLANATION

First solve for the slope:
$m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{0 - \frac{3}{5} }{ \frac{1}{2} - \frac{1}{5} } \\ m = - \frac{1}{5}$
After finding the slope, look for the linear equation with the same value of m (parallel equation).

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3 years ago

Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees

lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e. $\mu=0$ and $\sigma= 1$

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

$P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035$

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

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3 years ago