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3 years ago

7

Given the figure shown at the right ABC is a triangle, what would be the measure of the unknown exterior angle (labeled x in the

diagram)?

1 answer:

Andre45 [30]3 years ago

4 0

Answer:

d. 112°

Step-by-step explanation:

m<A = 64° (given)

m<ABC = 180° - 132° (linear pair)

m<ABC = 48°

According to the exterior angle theorem of a triangle, the exterior angle of a ∆ is equal to the opposite interior angles of the ∆.

48° and 64° are interior angles of ∆ABC that are opposite to the exterior angle, x.

Therefore,

x = 48 + 64

x = 112°

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I REALLY NEED HELP PLEASE!!

disa [49]

part A)

$\bf \begin{array}{ccllll}
hours(x)&velocity(y)\\
-----&-----\\
1&6\\
3&2
\end{array}\\\\
-------------------------------\\\\$

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 6}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ 2}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-6}{3-1}\implies \cfrac{-4}{2}\implies -2$

$\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-6=-2(x-1)\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-6=-2x+2\implies y=-2x+2+6\implies \boxed{y=-2x+8}$

part B)

well, we know y = -2x+8.... so.. what's the runner's velocity after 5hours? well, x = 5, thus y = -2(5) +8 ---> y = -2

to graph it, well, is a LINEar equation, meaning the graph is a LINE, and to graph a line, all you need is two points, and by now, you have more than two.. so graph it away.

7 0

3 years ago

What is the slope of the line given by the equation -3x = 30 - 5y?

zaharov [31]

Answer:

The slope of the line given by the equation -3x=30-5y is $\frac{3}{5}$ .

Step-by-step explanation:

-3x=30-5y

Move the -3x to the right side of the equal sign and the -5y to the left.

5y=30+3x

By switching them to opposite sides, their sign changes from - to +.

Then, divide both sides by 5 in order to isolate the y.

$\frac{5y}{5} = \frac{30+3x}{5}$

You get:

<em>y= </em> $\frac{3}{5} x +6$ <em />

According to y=mx+b, mx refers to the slope.

In this case, the slope would be $\frac{3}{5}$ .

8 0

3 years ago

1. Find the derivative of f(x), at x = 10<br> f(x) = - 5x² + 13x

Serhud [2]

Answer:

-10x+13

Step-by-step explanation:

Im not 100% sure but i tried!

6 0

3 years ago

Line segment AB has vertices A(-3, 4) and B(1, -2). A dilation centered at the orgin is applied to AB. The image has vertices A(

bixtya [17]

Answer:

option 2

Step-by-step explanation:

consider the coordinates A (- 3, 4 ) and A' (- 1, $\frac{4}{3}$ )

since the dilatation is centred at the origin, then corresponding coordinates are multiples/ divisors of each other, then image to original gives scale factor.

scale factor = $\frac{A'}{A}$ = $\frac{-1}{-3}$ = $\frac{1}{3}$ and $\frac{\frac{4}{3} }{4}$ = $\frac{1}{3}$

similarly B (1, - 2 ) and B' ( $\frac{1}{3}$ , - $\frac{2}{3}$ )

$\frac{\frac{1}{3} }{1}$ = $\frac{1}{3}$ and $\frac{-\frac{2}{3} }{-2}$ = $\frac{1}{3}$

4 0

2 years ago

The equation of a circle is given below.

BARSIC [14]

<u>Given</u>:

The equation of the circle is $x^2+(y+4)^2=64$

We need to determine the center and radius of the circle.

<u>Center</u>:

The general form of the equation of the circle is $(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center of the circle and r is the radius.

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the center.

The given equation can be written as,

$(x-0)^2+(y+4)^2=64$

Comparing the two equations, we get;

(h,k) = (0,-4)

Therefore, the center of the circle is (0,-4)

<u>Radius:</u>

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the radius.

Hence, the given equation can be written as,

$x^2+(y+4)^2=8^2$

Comparing the two equation, we get;

$r^2=8^2$

$r=8$

Thus, the radius of the circle is 8

3 0

3 years ago