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nevsk [136]
4 years ago
5

AB is tangent to O. If AO = 32 and BC = 98, what is AB? my guess is 130? please help!

Mathematics
2 answers:
rjkz [21]4 years ago
8 0
AO=CO
two congruent radii

Triangle ABO is a right-angled triangle

AO=32
BO=BC+CO=98+32=130
AB=\sqrt{(121^2-32^2)}= \sqrt{15876} =126

That is it!

Done :)

Use Pythagoras to calculate AB:



Juli2301 [7.4K]4 years ago
7 0
    
CO = AO  = 32    (Are rays.)
BO = BC + CO = 98 + 32 = 130
AB ⊥ BO
⇒  ΔAOB   is a rectangular triangle.
We use Pitagora's theorem.


\displaystyle\\
AB =  \sqrt{BO^2 - AO^2}  = \sqrt{130^2 -32^2}=\\\\
= \sqrt{16900 -1024}= \sqrt{15876}= \boxed{126 }



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